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4 years ago

An isometry preserves orientation distance direction

Physics

2 answers:

elena-s [515]4 years ago

8 0

Answer:

Distance

Explanation:

Isometry preserves the distance while transformation is made in between metric spaces. When a metric space is mapped on to another or itself, the distance between two points remains same in the images in the mapped space as well. Example: rotation and translation.

Thus, isometry preserves the distance.

hjlf4 years ago

6 0

Answer:

distance

Explanation:

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In a science fiction novel two enemies, Bonzo and Ender, are fighting in outer spce. From stationary positions, they push agains

lara [203]

Answer:

ratio of the masses of the two enemies = 1.7

Explanation:

Applying the law of conservation of momentum,

Momentum fo Bonzo = Momentum of Ender

mv = m'v'................. Equation 1

Where m = mass of Bonzo, v = velocity of Bonzo, m' = mass of Ender, v' = velocity of Ender

m/m' = v'/v............... Equation 2

Where m/m' = ratio of the masses of the two enemies

Given: v = 2.0 m/s, v' = 3.4 m/s

Substitute into equation 2

m/m' = 3.4/2

m/m' = 1.7

Hnece, ratio of the masses of the two enemies = 1.7

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3 years ago

How many poles in a rolo?

Yakvenalex [24]

Answer: 7

Explanation:

How many pieces are in a ROLO tube?

each classic roll of ROLO….has seven individually wrapped pieces. Tuck it in your lunchbox, bag or desk drawer and get your roll on.

3 0

3 years ago

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Consider a air-filled parallel-plate capacitor with plates of length 8 cm, width 5.52 cm, spaced a distance 1.99 cm apart. Now i

prohojiy [21]

Answer:

The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

Explanation:

Given that,

Length of plates = 8 cm

Width = 5.52 cm

Distance = 1.99 cm

Dielectric constant = 2.6

Length = 4.4 cm

Potential = 0.8 V

We need to calculate the initial capacitance

Using formula of capacitance

$C=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C=\dfrac{8.85\times10^{-12}\times8\times5.52\times10^{-4}}{1.99\times10^{-2}}$

$C=1.96\times10^{-12}$

We need to calculate the final capacitance

Using formula of capacitance

$C'=\dfrac{\epsilon_{0}A_{1}}{d}+\dfrac{k\epsilon_{0}A_{2}}{d}$

Put the value into the formula

$C'=(\dfrac{8.85\times10^{-12}}{1.99\times10^{-2}})((4.4\times5.52)+(3.6\times5.52)2.6)\times10^{-4}$

$C'=3.37\times10^{-12}$

We need to calculate the ratio of the new potential energy to the potential energy before the insertion of the dielectric

Using formula of energy

$\dfrac{E}{E'}=\dfrac{\dfrac{1}{2}CV^2}{\dfrac{1}{2}C'V^2}$

Put the value into the formula

$\dfrac{E}{E'}=\dfrac{1.96\times10^{-12}}{3.37\times10^{-12}}$

$\dfrac{E}{E'}=0.58$

Hence, The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

4 0

4 years ago

You have a spool of copper wire 4.82 mm in diameter and a power supply. You decide to wrap the wire tightly around a soda can th

GalinKa [24]

To solve the problem it is necessary to have the concepts of the magnetic field in a toroid.

A magnetic field is a vector field that describes the magnetic influence of electric charges in relative motion and magnetized materials.

By definition the magnetic field is given by the equation,

$B=\frac{\mu_0 NI}{2\pi r}$

Where,

$\mu_0$ = Permeability constant

N = Number of loops

I = Current

r = Radius

According to the given data we have that the length is 120mm and the thickness of the copper wire is 4.82mm.

In this way the number of turns N would be

$N=\frac{120mm}{4.82mm}$

$N = 24.89 \approx 25 turns$

On the other hand to find the internal radius, we know that:

$2\pi r_i = 12cm$

$r_i= \frac{12}{2\pi}$

$r_i= 1.91cm$

Therefore the total diameter of the soda would be

$r= r_i+r_o = 1.91+6.5=8.51cm$

Applying the concept related to magnetic field you have to for the internal part:

$B_i=\frac{\mu_0 NI}{2\pi r_i}$

$B_i=\frac{(4\pi*10^{-7}) (25)(230)}{2\pi (1.91*10^{-2})}$

$B_i = 0.060T$

The smallest magnetic field would be on the outside given by,

$B_o=\frac{\mu_0 NI}{2\pi r}$

$B_o=\frac{(4\pi*10^{-7}) (25)(230)}{2\pi 8.51}$

$B_o = 0.0136T$

<em>Therefore the maximum magnetic field is 0.06T.</em>

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4 years ago

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stira [4]

the strength and vitality required for sustained physical or mental activity.

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4 years ago

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