The equation of the parabolas given will be found as follows:
a] general form of the parabolas is:
y=k(ax^2+bx+c)
taking to points form the first graph say (2,-2) (3,2), thus
y=k(x-2)(x-3)
y=k(x^2-5x+6)

taking another point (-1,5)
5=k((-1)^2-5(-1)+6)
5=k(1+5+6)
5=12k
k=5/12
thus the equation will be:
y=5/12(x^2-5x+6)

b] Using the vertex form of the quadratic equations:
y=a(x-h)^2+k
where (h,k) is the vertex
from the graph, the vertex is hence: (-2,1)
thus the equation will be:
y=a(x+2)^2+1
taking the point say (0,3) and solving for a
3=a(0+2)^2+1
3=4a+1
a=1/2
hence the equation will be:
y=1/2(x+2)^2+1

5 0

3 years ago

Kate currently has an account balance of $7,194.66. She opened the account 21 years ago with a deposit of $2,978.41. If the inte

jolli1 [7]

Use the attached formula.
exp = [log (total / principal) / n*years]
where "n" is compounding periods per year
exp = [log (7,194.66 / 2,978.41) / (365*21)
exp = log ( 2.4156042989 ) / 7,665
exp = log ( 2.4156042989 ) / 7,665
exp = 0.38302579382 / 7,665
exp = 0.00004997074935681670 

rate = (10^exp -1)* n
rate = (10^0.00004997074935681670 -1) * n
rate = (1.0001150685 -1) * 365
rate = (.0001150685) * 365
rate = 0.0420000025 
rate = 4.20000025 %
rate = 4.2 %

Yes, it's just that easy. LOL

5 0

3 years ago

Read 2 more answers

Twelve and twenty nine hundredths in number form

kobusy [5.1K]

Answer:

12.29

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers