Suppose you have 8 coins and you have at least one each of a quarter, a dime, and a penny. What is the least amount of money you
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Answer:
y+11=-(x-4)
Step-by-step explanation:
since the equation is perpendicular to y=4x-2, m=-1/4 (negative reciprocal). (x_1,y_1)=(4,-11), plug all the values into the equation y- y_1 = m(x-x_1) and we get y+11=-(x-4)