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IgorLugansk [536]
3 years ago
9

Suppose you have 8 coins and you have at least one each of a quarter, a dime, and a penny. What is the least amount of money you

could have?
Mathematics
1 answer:
Black_prince [1.1K]3 years ago
4 0

41 cents one quarter one dime six pennies

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17 − 2v = 41 solve v
anastassius [24]

17-2V=41

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The odds of flipping a fair coin either heads or tails is 50%. The odds of rolling a six on a fair six sided die is 16.6% or 1 i
creativ13 [48]

Answer:

P( sum is prime )= 73/216

Step-by-step explanation:

The minimum value of the sum will be 3 and maximum value will be 18. So the prime numbers in this range are 3 , 5, 7, 11, 13, 17.

P(sum=3)=1/216, P(sum=5)=6/216, P(sum=7)=15/216, P(sum=11)=27/216, P(sum=13)=21/216, P(sum=17)=3/216.

The final probability will be sum of the above given probabilities.

Hence P( sum is prime )= 73/216

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