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antiseptic1488 [7]
2 years ago
8

A cow can give 5 gallons of milk if it eats 2 pounds of grass. Express x in terms of y, where y is the number of gallons of milk

the cow gives, and x is the number of pounds of grass it eats.
Mathematics
1 answer:
Crank2 years ago
4 0

Answer:y=2.5 x

Step-by-step explanation:

Given

Cow give 5 gallon of milk if it eats 2 pound of grass

i.e. it gives 2.5 gallon of milk if it eats 1 pound of grass

So we can say cow given 2.5 times of milk in gallon for each pound it eats

If cow eats x pounds of grass then it must yield 2.5 times of milk

Suppose milk is denoted by y  

therefore we can write

y=2.5 x

Therefore y=2.5 x represent the relation between grass and milk produced

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Find the volume of this cone.
Andrews [41]

Answer:

V = 180 ft^3

Step-by-step explanation:

The volume of a cone is found by

V = 1/3 pi r^2 h  where r is the radius and h is the height

The diameter is 12 so the radius is 1/2 the diameter or 1/2(12) = 6

The height is 5 and we are using 3 for pi

V = 1/3 (3) *6^2 *5

V = 180 ft^3

4 0
2 years ago
Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2
Vsevolod [243]

Answer:

Given that:

a = (\frac{x+ip}{2})^{\frac{1}{2}} and a+= (\frac{x-ip}{2})^{\frac{1}{2}}

if a , a+ commutator, it obeys aa^+ = a^+a

First find:

aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}

                = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

Now;

a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}

              =(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

therefore, aa^+ = a^+a which implies the operators a and a+ are commutators.    


7 0
3 years ago
The area of trapezoid TRAP is 100 m squared
Anastasy [175]
Answer:  30 m ; (or, write as: "30 meters") .
______________________________________________
Explanation:
____________________

Area of a trapezoid, "A" = (1/2) ( b₁ + b₂) h ;
______________________________________________
or, write as:  A = ( b₁ + b₂) h  / 2 ;
___________________________________
in which:  A = area;
              b₁ = length of "base 1" (choose either one of the 2 (two bases);
              b₂ = length of "base 2" (use the base that is remaining);
              h = height of trapezoid;
____________________________________________
From the information given: 
___________________________
A = 100 m² ; 
h = 5 m
b₁ = 10 m
b₂ =  x 
___________________________
Find "x", which is:  "b₂" ;
__________________________
      A = ( b₁ + b₂) h  / 2  ;
_____________________________
Plug in our known values; and plug in "x" for "b₂" ; and solve for "x" ;
_________________________________________________________
  100 m² = [(10m + x) (5m)] / 2  ; Solve for "x" ;
_________________________________________________________
          (10m + x) (5m) = (2)* (100m²) ;
_________________________________________________________
             (5m) (10m + x) = 200 m² ;
___________________________________________
Note:  The distributive property of multiplication:
____________________________________________
    a(b+c) = ab + ac ;
 
    a(b−c) = ab <span>− ac ;
</span>____________________________________________

  We have:  (5m) (10m + x) = 200 m²  ;
____________________________________________
So:    (5m) (10m + x) =  (5m*10m) + (5m * x) ;
                           
                               =  50m² + (5m)x  ;
_______________________________________________
     →  50m² + (5m)x = 200m²  ; 
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Divide the ENTIRE equation by "5m" ;
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     → { 50m² + (5m)x } / 5m = (200m² / 5m) ;
_______________________________________________
     →  10m + x   = 40m ; 
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Now, subtract "10m" from EACH side of the equation; to isolate "x" on one side of the equation; and to solve for "x" ;
_______________________________________
     →  10m + x  − 10m  =  40m − 10m ;

to get:

                →    x  =  30 m  ; which is our answer.
___________________________________________________
Answer:  30 m ; (or, write as: "30 meters") .
_____________________________________________________
6 0
3 years ago
The owner purchases 5 buckets, 10 brushes, 48 towels, and 1 case of air fresheners for the car wash. The total cost of the purch
Allushta [10]
5 buckets at $2.89 = 5($2.89) = $14.45
10 brushes at $7.91 = 10($7.91) = $79.10
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These three added together makes $110.83.  This leaves us $144.08-$110.83=$33.25 for the cost of the case of air fresheners.
8 0
3 years ago
Can someone PLEASE help with this
Afina-wow [57]

Answer: 226.19

Step-by-step explanation:

5 0
2 years ago
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