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LiRa [457]
1 year ago
7

Convert these unlike fractions to equivalent like fractions and add them. You must use the lcd to get the answer correct. If pos

sible, reduce the final sum. 14512.
Mathematics
1 answer:
ra1l [238]1 year ago
4 0

Unlike fraction 1/7 is converted to equivalent  like fraction 2/14 and the sum of 2/14 + 3/14 = 5/14.

As given in the question,

Given fraction is equal to:

1/7=? + 3/14=?

Here there are two fractions

1/7 and 3/14

LCD( least common denominator) of 7 and 14 is equal to 14.

Now make them like fractions

1/7 is equivalent to

( 1/7) × ( 2/2) = 2/ 14

Now 2/14 and 3/14 are like fractions

Sum of like fractions is:

2/14 + 3/14

= ( 2+ 3) / 14

= 5/ 14

Therefore, the conversion of unlike fraction 1/7 to like fraction is 2/14. And sum of 2/14 + 3/14 = 5/14.

The complete question is:

Convert these unlike fractions to equivalent like fractions and add them. You must use the LCD to get the answer correct. If possible, reduce the final sum. 1/7=? + 3/14=?

Learn more about fractions here

brainly.com/question/10354322

#SPJ4

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If a thousand dollars is put into a bank account each year the account earns 7% simple interest in 4 years how much interest wou
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$280

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According to the problem, calculation of the given data are as follows:

Principal amount (P) = $1,000

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8 0
3 years ago
The length of a rectangular field is 7 m less than 4 times the width. The perimeter is 136 m. Find the width and the length
Helga [31]

Answer:

Step-by-step explanation:

Represent the width by W.  Then, "The length of a rectangular field is 7 m less than 4 times the width" expressed symbolically is

L = 4W - 7 (dimensions in meters)

Recall that the perimeter formula in this case is P = 2L + 2W, and recognize that the perimeter value is 136 m.  After substituting 4W - 7 for L, we get:

136 m = 2(4W - 7) + 2W, or

136 = 8W - 14 + 2W, or

150 = 10W        These three equations are equivalent mathematical statements.

150 = 10W reduces to W = 15 (meters).

Part A:  the independent variable is W, the width of the field.

Part B:  The mathematical statement is 136 m = 2(4W - 7) + 2W, which after algebraic manipulation becomes 150 = 10W.

Part C:  The above equation can be solved for W:  W = 15 meters.  This is the value of the independent variable.

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