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2 years ago

How many 9-inch-square floor tiles are needed to cover a rectangular floor that measures 12 feet by 15 feet?

1 answer:

6 0

To cover the width we need 12÷¾=12×4/3=16 tiles.
To cover the length we need 15×4/3=20 tiles, so to cover the floor area we need 16×20=320 tiles.

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Step-by-step explanation:

When solving this equation use the distributive property and get...

-4 (y - 2) = 12

-4y + 8 = 12

-4y = 12 - 8

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Read 2 more answers

The coordinates of parallelogram UVWZ are U(a, 0), W(c - a, b), and Z(c, 0). Find the coordinates of V without using any new var

UkoKoshka [18]

Check the picture below.

so, as you can see, the UV segment is parallel to ZW, and therefore, they're the same slope, hmmm wait just a second, what is the slope of ZW anyway?

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&Z&(~ c &,& 0~) 
% (c,d)
&W&(~ c-a &,& b~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{b-0}{(c-a)-c}\implies \cfrac{b}{-a}$

since now we know the ZW slope, we also know what is the slope for UV, thus,

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&U&(~ a &,& 0~) 
% (c,d)
&V&(~ x &,& y~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{y-0}{x-a}~~=~~\stackrel{ZW's~slope}{\cfrac{b}{-a}}
\\\\\\
\begin{cases}
y-0=b\implies \boxed{y=b}\\
-----------\\
x-a=-a\implies \boxed{x=0}
\end{cases}\qquad \qquad V~(0,b)$

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3 years ago

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Zanzabum

This might help each line tick is 1

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3 years ago

How many 9-inch-square floor tiles are needed to cover a rectangu­lar floor that measures 12 feet by 15 feet?

How many 9-inch-square floor tiles are needed to cover a rectangular floor that measures 12 feet by 15 feet?