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Law Incorporation [45]
2 years ago
5

How many 9-inch-square floor tiles are needed to cover a rectangu­lar floor that measures 12 feet by 15 feet?

Mathematics
1 answer:
Eduardwww [97]2 years ago
6 0
To cover the width we need 12÷¾=12×4/3=16 tiles.
To cover the length we need 15×4/3=20 tiles, so to cover the floor area we need 16×20=320 tiles.
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Function f is graphed. According to the graph, is f even, odd, or neither?
miss Akunina [59]

Answer:

C

Step-by-step explanation:

f is neither even nor odd

3 0
3 years ago
Someone please help me on this question ?:)
katrin2010 [14]

Answer: The TV is 48 inches wide.

Step-by-step explanation: To find the solution to this equation we must use the Pythagorean theorem. The Py. Theo. is basically the formula :

a^2 + b^2 = c^2    You say this as "A squared plus b squared equals c squared"

To use this formula you must plug in the given values of a and b, to find c. A and b represent the two bases of the triangle, while c is the hypotenuse. In this equation we already have the value of c and a. We need to find b, but in order to do that we use a different formula. We use : c^2 - a^2 = b^2

See :

52^2 - 20^2 = b^2       *The ^2 means "to the power of" aka an exponent*

2704 - 400 = b^2     *When dealing with ^2, all you do is multiply the number by itself*

2304 = b^2      *Next, we find the square root of our current number.*

48 = b    

*Another way to solve this equation is to memorize all the Pythagorean Triples. With that knowledge, you wont even need to use the formula because you will already know all three values. I hope this helped you understand :)



3 0
3 years ago
2. What if Janelle began by running, then slowed to a walk, stopped, and then began running
stealth61 [152]
I think it is A
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7 0
3 years ago
14. The cost of 10 dozen of caps is Rs.800. How many caps can bebought for Rs.200.​
Mashcka [7]

Answer:

Step-by-step explanation:

10 dozen is equal to 120 so ratio is 800/120 or 80/12

same ration on the other side but 200/x.Cross multiply and u get 3

7 0
3 years ago
Solving a trigonometric equation involving an angle multiplied by a constant
PIT_PIT [208]

In these questions, we need to follow the steps:

1 - solve for the trigonometric function

2 - Use the unit circle or a calculator to find which angles between 0 and 2π gives that results.

3 - Complete these angles with the complete round repetition, by adding

2k\pi,k\in\Z

4 - these solutions are equal to the part inside the trigonometric function, so equalize the part inside with the expression and solve for <em>x</em> to get the solutions.

1 - To solve, we just use algebraic operations:

\begin{gathered} \sqrt[]{3}\tan (3x)+1=0 \\ \sqrt[]{3}\tan (3x)=-1 \\ \tan (3x)=-\frac{1}{\sqrt[]{3}} \\ \tan (3x)=-\frac{\sqrt[]{3}}{3} \end{gathered}

2 - From the unit circle, we can see that we will have one solution from the 2nd quadrant and one from the 4th quadrant:

The value for the angle that give positive

+\frac{\sqrt[]{3}}{3}

is known to be 30°, which is the same as π/6, so by symmetry, we can see that the angles that have a tangent of

-\frac{\sqrt[]{3}}{3}

Are:

\begin{gathered} \theta_1=\pi-\frac{\pi}{6}=\frac{5\pi}{6} \\ \theta_2=2\pi-\frac{\pi}{6}=\frac{11\pi}{6} \end{gathered}

3 - to consider all the solutions, we need to consider the possibility of more turn around the unit circle, so:

\begin{gathered} \theta=\frac{5\pi}{6}+2k\pi,k\in\Z \\ or \\ \theta=\frac{11\pi}{6}+2k\pi,k\in\Z \end{gathered}

Since 5π/6 and 11π/6 are π radians apart, we can put them together into one expression:

\theta=\frac{5\pi}{6}+k\pi,k\in\Z

4 - Now, we need to solve for <em>x</em>, because these solutions are for all the interior of the tangent function, so:

\begin{gathered} 3x=\theta \\ 3x=\frac{5\pi}{6}+k\pi,k\in\Z \\ x=\frac{5\pi}{18}+\frac{k\pi}{3},k\in\Z \end{gathered}

So, the solutions are:

x=\frac{5\pi}{18}+\frac{k\pi}{3},k\in\Z

4 0
1 year ago
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