Answer:
Step-by-step explanation:
The key fact is what are the trains doing: are they travelling toward one another or away from each other
Away from each other.
Train A has gone 50 km in 1 hour
Train B has gone 65 km in 1 hour.
They started off being 200 km apart
So their distance now is 50 + 65 + 200 = 315
Towards each other
This time they are eating into the 200 km
So you subtract
200 - 65 - 50 = 200 - 115 = 85 km.
Both trains are travelling in the same direct -- in B's direction
B - 65 + 50
200 - 15
185 km
Both trains are travelling in As direction
A - 50 + 65
200 + 15 = 215
The tricky part of this is which train is going in what direction?
As you can see, You have covered A C and D
The only one can't get is 115 (of course 315 didn't show up either).
The ratio of 8/4 is 2:1 because 8/4 divided by 4 equals 2/1 which equals 2:1
Step-by-step explanation:
x is the independent variable
y is the dependent variable
Answer:
a) ∫_{-6}^{6} ∫_{0}^{36} ∫_{x²}^{36} (-y) dy dz dx
b) ∫_{0}^{36} ∫_{-6}^{6} ∫_{x²}^{36} (-y) dy dx dz
c) ∫_{0}^{36} ∫_{x²}^{36} ∫_{-6}^{6} (-y) dx dy dz
e) ∫_{x²}^{36} ∫_{-6}^{6} ∫_{0}^{36} (-y) dz dx dy
Step-by-step explanation:
We write the equivalent integrals for given integral,
we get:
a) ∫_{-6}^{6} ∫_{0}^{36} ∫_{x²}^{36} (-y) dy dz dx
b) ∫_{0}^{36} ∫_{-6}^{6} ∫_{x²}^{36} (-y) dy dx dz
c) ∫_{0}^{36} ∫_{x²}^{36} ∫_{-6}^{6} (-y) dx dy dz
e) ∫_{x²}^{36} ∫_{-6}^{6} ∫_{0}^{36} (-y) dz dx dy
We changed places of integration, and changed boundaries for certain integrals.
Answer:
33.3% probability that both children are girls, if we know that the family has at least one daughter named Ann.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
The family has two children.
The sample space, that is, the genders of the children may be divided in the following way, in which b means boy and g means girl.
b - b
b - g
g - b
g - g
We know that they have at least one girl. So the sample space is:
b - g
g - b
g - g
What is the probability that both children are girls, if we know that the family has at least one daughter named Ann?
Desired outcomes:
Both children being girls, so
g - g
1 desired outcome
Total outcomes
b - g
g - b
g - g
3 total outcomes
Probability
1/3 = 0.333
33.3% probability that both children are girls, if we know that the family has at least one daughter named Ann.
