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2 years ago

Jason types papers for local college students. He charges $6.50 per page. How much will he receive for a 22 page paper?

Mathematics

2 answers:

Archy [21]2 years ago

8 0

Answer: He will receive $143 for a 22 page paper.

Step-by-step explanation: Simply multiply $6.50 by 22 to find the total Jason will charge for a 22 page paper.

6.50 x 22 = 143

So, Jason will charge $143 for a 22 page paper.

Gelneren [198K]2 years ago

4 0

Answer:

$143

Step-by-step explanation:

$6.50 times 22= $143

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What is the remainder R when the polynomial p(x) is divided by (x + 1)? Is (x + 1) a factor of p(x)? p(x) = -3x4 + 2x3 - x2 + 6

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(x+1) is a factor with remainder 0.

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We divide (x+1) into the polynomial $-3x^4+2x^3-x^2+6$ through long division or synthetic. We choose long division and look for what will multiply with (x+1) to make the polynomial $-3x^4+2x^3-x^2+6$ .

$(x+1)(-3x^3)=-3x^4-3x^3$

We subtract this from the original $-3x^4-(-3x^4)+2x^3-(-3x^3)-x^2+6$ .

This leaves $5x^3-x^2+6$ . We repeat the step above.

$(x+1)(5x^2)=5x^3+5x^2$ .

We subtract this from $5x^3-(5x^3)-x^2-(5x^2)+6=-6x^2+6$ . We repeat the step above.

$(x+1)(-6x)=-6x^2-6x$ .

We subtract this from $-6x^2-(-6x^2)+0x-(-6x)+6=6x+6$ . We repeat the step above.

$(x+1)(6)=-6x+1$ .

We subtract this from $6x-(6x)+6-(6)=0$ . There is no remainder. This means (x+1) is a factor.

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