Answer:
The answer is 2/3 and I will show the working to prove that in the explanation
Step-by-step explanation:
÷ 
×
Answer =× = 
- So basically what is happening in the above steps what I have shown is that first I am changing the division sign into multiplication and then I am reciprocating the fraction of 1/4 into 4/1 because on the other side of it is multiplying and after doing that I am simplifying the fraction 4/6 by dividing it by 2 and hence I got a fraction of 2/3 as the answer
Answer:
4) 16√3 in²
5) 63 cm²
Step-by-step explanation:
The formula to use in these cases is ...
A = (1/2)ab·sin(θ)
where a, b are the side lengths and θ is the angle between them.
It helps to know the trig functions of the "special" angles used here.
sin(120°) = sin(60°) = (√3)/2
cos(60°) = 1/2
sin(135°) = cos(45°) = (√2)/2
__
4) The external angle at the base is the supplement of 120°, so is 60°. Then the length of the missing segment between the end of the base and the right angle at h is ...
x = (8 in)cos(60°) = (8 in)(1/2) = 4 in
So, the bottom edge of the triangle is 12 in - 4 in = 8 in.
The area is ...
A = (1/2)(8 in)(8 in)sin(120°) = (1/2)64(√3)/2 in² = 16√3 in²
__
5) As in the previous problem, the difference between the given horizontal dimension and the base of the triangle is ...
x = (18 cm)cos(180°-135°) = 18(√2)/2 cm = 9√2 cm
Then the base of the triangle is ...
16√2 cm -9√2 cm = 7√2 cm
The area is then ...
A = (1/2)(18 cm)(7√2 cm)(√2)/2 = 63 cm²
X^2^4 = x^8
Just multiply then 2 and 4 to get 8
Answer: The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
Step-by-step explanation:
I will assume that the exercise says "
times the base and height of Jerry’s rhombus".
The area of a rhombus can be calculated with the following formula:
Where "b" is the length of the base and "a" is the altitude or the height.
Then, you can calculate the area using the formula shown above.
Therefore, you get:
1. Jerry's rhombus:
2. Charlene's rhombus:
Dividing the area calculated, you get:
Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
