Solve for x over the real numbers:
x^3 (x^2 - 4) = 0
Split into two equations:
x^3 = 0 or x^2 - 4 = 0
Take cube roots of both sides:
x = 0 or x^2 - 4 = 0
Add 4 to both sides:
x = 0 or x^2 = 4
Take the square root of both sides:
Answer: x = 0 or x = 2 or x = -2
Question a:
f(6) = (6)² + 2(6) + 8
f(6) = 36 + 12 + 8
f(6) = 56
Question b:
f(x+4) = (x+4)² + 2(x+4) + 8
f(x+4) = x² + 8x + 16 + 2x + 8 + 8
f(x+4) = x² + 10x + 32
Question c:
f(-x) = (-x)² + 2(-x) + 8
f(-x) = x - 2x + 8
86, 90, and 92
Explanation:add all numbers together and divide it by the amount of numbers there are (5) and it comes out with 85.6 so it has to be higher since it increased
Answer:
4032 integers.
Step-by-step explanation:
Lest start with -2016. There are 2016 integers from -2016 to 0. Then we see how many integers are from 0 to 2016. there are 2016. If you add them up, you get 4032.
