Answer:
There can be at most
attendees in a corporate team-building event.
Step-by-step explanation:
Let
denotes number of attendees in a corporate team-building event.
Fixed cost = $19
Cost charged per attendee = $1
Budget for the corporate team-building event = $31
Therefore,

So, there can be at most
attendees in a corporate team-building event.
we know that
step 1
multiply
by 
so

step 2
Divide numerator and denominator by 

therefore
the answer is

Answer:
more than likely its
f(1) -5
Step-by-step explanation:
Answer:
7.9
Step-by-step explanation:
the first thing to do is find the second projection.
16-7 = 9
than we can use a proportion to find BD
7 : BD = BD : 9
BD = √9 x 7 = √63 = 7.9
we have to use the square root because in the proportion BD Is repeated two times. If we don’t use it, we find BD^2