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3 years ago

An ant looks up to the top of a tree with an angle of elevation of 38 degrees

Mathematics

1 answer:

Katarina [22]3 years ago

3 0

Height = H
Angle € = 38°
Length L = 43 ft
Sin € = opposite/adjacent
Sin 38 = H / 43
43×sin38 = H
H = 26.47 ft

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In its monthly report, the local animal shelter states that it currently has 24 dogs and 18 cats available for adoption. Eight o

andrezito [222]

Answer with Step-by-step explanation:

We are given that

Total dogs=24

Total cats=18

Total animals=24+18=42

Male dogs=8

Male cats=6

Total male animals=8+6=14

Total female animals=42-14=28

Female cats=18-6=12

Dogs female=24-8=16

a.We have to find the probability that the pet is male, given that it is cat.

It means we have to find P(Male/cat)

Conditional probability: $P(A/B)=\frac{P(A\cap B)}{P(B)}$

P(Cat)= $\frac{18}{42}$

$P(male cat)=\frac{6}{42}$

$P(Male/cat)=\frac{\frac{6}{42}}{\frac{18}{42}}$

P(male/cat)= $\frac{6}{18}=0.33$

b. $P(female cat)=\frac{12}{42}$

$P(female)=\frac{28}{42}$

$P(Cat/Female)=\frac{\frac{12}{42}}{\frac{28}{42}}=\frac{12}{28}=0.43$

c.P(Dog)= $\frac{24}{42}$

$P(dog female)=\frac{16}{42}$

$P(female/dog)=\frac{\frac{16}{42}}{\frac{24}{42}}$

$P(female/dog)=\frac{16}{24}=0.67$

5 0

3 years ago

In 2000 the total amount of gamma ray bursts was recorded at 6.4 million for a city. In 2005, the same survey was made and the t

ratelena [41]

Let's assume

It started in 2000

so, t=0 in 2000

$P_0=6.4million$

we can use formula

$P(t)=P_0 e^{rt}$

we can plug value

$P(t)=6.4 e^{rt}$

In 2005, the same survey was made and the total amount of gamma ray bursts was 7.3 million

so, at t=2005-2000=5

P(t)=7.3 million

we can plug value and then we can solve for r

$7.3=6.4 e^{r*5}$

$r=0.02632$

now, we can plug back

$P(t)=6.4 e^{0.02632t}$

now, we have

P(t)=1 billion =1000 million

so, we can set it and then we can solve for t

$1000=6.4 e^{0.02632t}$

$t=191.924$

approximately

$t=192$

Year is 2000+192

year is 2192................Answer

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Answer:

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Answer:

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Step-by-step explanation:

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Answer:

300 days of work.

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He needs to work for 300 days for 2 dollars a day to get 600 dollars:

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