Factor completely 2w^5-10w^3

Mathematics

1 answer:

Kryger [21]3 years ago

8 0

$2w^5-10w^3=2w^3(w^2-5)$

You might be interested in

Mark cast a shadow that is 4 feet long. At the same time, a nearby tree casts a shadow that is 20 feet long. If mark is 6 feet t

Trava [24]

Answer:

30 ft

Step-by-step explanation:

We can use the given information to set up a ratio...

$\frac{Mark's\ height}{Mark's\ shadow}=\frac{Tree's\ height}{Tree's\ shadow}$

$\frac{6\ ft}{4\ ft}=\frac{x}{20\ ft}$

We can solve this ratio using cross multiplication (multiply the numerator of the first fraction by the denominator of the second and the numerator of the second fraction by the denominator of the first):

120 = 4x

Divide both sides by 4

x=30 ft

5 0

3 years ago

if you a coin and roll a 6-sided die , what is the probability that you will flip a tails and roll a 2?

Aleonysh [2.5K]

1/2 for a coin. 1/6 for a die. multiply them and u get 1/12 (you happy now weirkai27?) 1/12 is your answer.

brainliest?

4 0

3 years ago

What is the maximum number of relative extrema contained in the graph of this function f(x)=3x^3-x^2+4x-2

Sergeeva-Olga [200]

The maximum number of turning points in a cubic function is 2.

In this case,

$f(x)=3x^3-x^2+4x-2\implies f'(x)=9x^2-2x+4$

The discriminant is $(-2)^2-4(9)(4)=-140$ , which means the derivative has no real roots. This means there are no critical points and thus no turning points/relative extrema.