Hello!
To solve this, lets put it into a system of equations where w=width and L=length.
2w+2L=80
L-8=w
To solve, we see that w=L-8. We can substitute this in the first equation to find L and then w.
2(L-8)+2L=80
2L-16+2L=80
4L-16+80
4L-16=80
4L=96
L=24
Now that we know L=24, we can find w. 24-8=16. Now we know that L=24 and w=16.
Lets check our answer. In our original system of equations, we have 48+32=80, which is true, and 24-8=16. Also, the perimeter must equal 80. 16+16+24+24=80.
As our final answer, the width of the pool is 16 feet, and the length is 24 feet.
Hope this helps!
Answer:
8
Step-by-step explanation:
3 times 4 is 12 and 2 times 4 is 8
Answer:
p(2) =147 and p(4) = 1791
Step-by-step explanation:
We are given p(x)= 6x^4 + 4x^3 – 3x^2 + 8x + 15.
Now we need to find value of p(2) and p(4)
Put x =2,
p(2) = 6(2)^4 + 4(2)^3 – 3(2)^2 + 8(2) + 15
p(2) = 6(16)+4(8)-3(4)+8(2)+15
p(2) = 96+32-12+16+15
p(2) = 147
Now put x = 4
p(4) = 6(4)^4 + 4(4)^3 – 3(4)^2 + 8(4) + 15
p(4) = 6(256)+4(64)-3(16)+8(4)+15
p(4) = 1536+256-48+32+15
p(4) = 1791
D would be the correct answer.
Explanation
a^2+b^2=c^2
4^2+3^2=c^2
16+9
25 units
