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s2008m [1.1K]
3 years ago
12

Find an ordered pair (x,y) that is a solution to the equation 5x+y=7

Mathematics
2 answers:
lord [1]3 years ago
6 0

Answer:

(1 , 2)

Step-by-step explanation:

Given that:

5x+y=7

Now we have to find an ordered pair (x , y) which satisfies above equation

For (1 , 2) it means x =1 and y = 2 we get

5x+y=7

5 (1) + 2 = 7

5 + 2 = 7

7 = 7

Hence proved.

I hope it will help you.

IRINA_888 [86]3 years ago
4 0

Answer:

54565656

Step-by-step explanation:

ggfght

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Perpendicular slope: 3

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Translate this phrase into an algebraic expression.
alexira [117]

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Step-by-step explanation:

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n200080 [17]
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Please I need this before 12pm
luda_lava [24]

Answer:

The required formula is:

                                                          {\displaystyle \ a_{n}=a_{1}+(n-1)d}

Step-by-step explanation:

The total number of squares of the the first term = 4

The total number of squares of the the second term = 7

The total number of squares of the the third term = 10

so,

a_1=4

a_2=7

a_3=10

Finding the common difference d

d=a_3-a_2=10-7=3

d=a_2-a_1=7-4=3

As the common difference 'd' is same, it means the sequence is in arithmetic.

So

If the initial term of an arithmetic progression is {\displaystyle a_{1}} and the common difference of successive members is d, then the nth term of the sequence (a_n) is given by:

                         {\displaystyle \ a_{n}=a_{1}+(n-1)d}

Therefore, the required formula is:

                                                          {\displaystyle \ a_{n}=a_{1}+(n-1)d}

3 0
3 years ago
HELP ASAP. WILL GIVE BRAINLIEST.
AlladinOne [14]

Answer:

×=18+25=9²

Step-by-step explanation:

Hope this helps

4 0
3 years ago
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