Question

Find acceleration of a cheetah running at 0.5 and sect 21 and second three seconds describe the acceleration of the animal.

Answer 1

Answer:

Initial velocity (u)=o m/s

Final velocity (v)=27m/s

Time taken to attain velocity is(t)=5m/s

As we know v=u+at

Substitute above values in the given equation

27=0+a(5)

27/5=a

a=5.4 m/s^2

Step-by-step explanation: