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mixer [17]
3 years ago
11

To how many patrons could a telephone company furnish numbers having five digits, the first digit not being zero? I know the ans

wer is 90,000 im just wondering how to do it
Mathematics
1 answer:
blagie [28]3 years ago
3 0

Answer:

90,000

Step-by-step explanation:

Given

A Company has to provide 5-digit numbers(The first digit≠0)

This question can be solved with Permutations and Combinations

Assume there are 5 blank spaces representing any phone number

The first digit can be filled in 9 ways(excluding 0 ={1,2,3,4,5,6,7,8,9})

The second digit can be filled in 10 ways(no exemptions={0,1,2,3,4,5,6,7,8,9})

The third digit can be filled in 10 ways(no exemptions={0,1,2,3,4,5,6,7,8,9})

The fourth digit can be filled in 10 ways(no exemptions={0,1,2,3,4,5,6,7,8,9})

The fifth digit can be filled in 10 ways(no exemptions={0,1,2,3,4,5,6,7,8,9})

So total number of ways to fill the 5 blanks

=9\times10\times10\times10\times10\\=90000

⇒Total number of 5-digit phone numbers= 90000

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