Answer:
88.88% probability that it endures for less than a year and a half
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

The next career begins on Monday; what is the likelihood that it endures for less than a year and a half?
One year has 52.14 weeks. So a year and a half has 1.5*52.14 = 78.21 weeks.
So this probability is the pvalue of Z when X = 78.21.



has a pvalue of 0.8888
88.88% probability that it endures for less than a year and a half
F(x) = x^5 - 1; g(x) = 5x^2; h(x) = 2x
Answer:
Answer:138
Step-by-step explanation:
First plug in the c and d values into the expression:
6(5)^2-5(4)+8
Remember PEMDAS, so you do 5^2 first getting you 25.
6(25)-5(4)+8
Continue with PEMDAS and multiply -5 and 4, and that gets you -20.
150-20+8
Now you simplify the expression to get: 138.
The easiest way to determine the answer is to just divide $57/$60 = 0.95 or 95%
Answer:
The answer is A
Step-by-step explanation:
The point is at one then it goes up to 600 so yea