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gogolik [260]
3 years ago
7

REALLY NEED AN ALGEBRA 1 GENIUS RIGHT NOW!

Mathematics
1 answer:
Archy [21]3 years ago
6 0

are the answers pictures????

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Choose all of the equations that are equivalent to 8k = 20. 8k – 4 = 20 + 4 8k ÷ 4 = 20 ÷ 4 8k × 3 = 20 × 3 8k + 10 = 20 + 10 8k
Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

8 0
3 years ago
Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
NeX [460]

Answer:

(a) 0.343

(b) 0.657

(c) 0.189

(d) 0.216

(e) 0.353

Step-by-step explanation:

Let P(a vehicle passing the test) = p

                        p = \frac{70}{100} = 0.7  

Let P(a vehicle not passing the test) = q

                         q = 1 - p

                         q = 1 - 0.7 = 0.3

(a) P(all of the next three vehicles inspected pass) = P(ppp)

                           = 0.7 × 0.7 × 0.7

                           = 0.343

(b) P(at least one of the next three inspected fails) = P(qpp or qqp or pqp or pqq or ppq or qpq or qqq)

      = (0.3 × 0.7 × 0.7) + (0.3 × 0.3 × 0.7) + (0.7 × 0.3 × 0.7) + (0.7 × 0.3 × 0.3) + (0.7 × 0.7 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.3)

      = 0.147 + 0.063 + 0.147 + 0.063 + 0.147 + 0.063 + 0.027

      = 0.657

(c) P(exactly one of the next three inspected passes) = P(pqq or qpq or qqp)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

                 = 0.063 + 0.063 + 0.063

                 = 0.189

(d) P(at most one of the next three vehicles inspected passes) = P(pqq or qpq or qqp or qqq)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7) + (0.3 × 0.3 × 0.3)

                 = 0.063 + 0.063 + 0.063 + 0.027

                 = 0.216

(e) Given that at least one of the next 3 vehicles passes inspection, what is the probability that all 3 pass (a conditional probability)?

P(at least one of the next three vehicles inspected passes) = P(ppp or ppq or pqp or qpp or pqq or qpq or qqp)

=  (0.7 × 0.7 × 0.7) + (0.7 × 0.7 × 0.3) + (0.7 × 0.3 × 0.7) + (0.3 × 0.7 × 0.7) + (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

= 0.343 + 0.147 + 0.147 + 0.147 + 0.063 + 0.063 + 0.063

                  = 0.973  

With the condition that at least one of the next 3 vehicles passes inspection, the probability that all 3 pass is,

                         = \frac{P(all\ of\ the\ next\ three\ vehicles\ inspected\ pass)}{P(at\ least\ one\ of\ the\ next\ three\ vehicles\ inspected\ passes)}

                         = \frac{0.343}{0.973}

                         = 0.353

3 0
3 years ago
Read 2 more answers
A square mosaic is made of small glass squares. If there are 256 small squares in the mosaic how many are along an edge?
Degger [83]
To do this, you got to square 256.

The square root of 256 is 16.

Therefore, there are 16 small squares on each edge of the mosaic.

Kinda proof:

o  o  o  o  O
o  o  o  o  O
o  o  o  o  O
o  o  o  o  O
o  o  o  o  O

25 squares. Square root is 5. 5 along each edge. My work shares same concept.

Extremely unnecessary proof:

o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O
o   o   o   o   o   o   o   o   o   o   o   o   o   o   o   O

There are 256 squares, and you can count 16 on each edge. this shows 16 times 16, or 16 squared, which is 256.

3 0
3 years ago
Read 2 more answers
Make a histogram, using a bin width of ten, to display the bowling scores for these 31 players: 87, 104, 79, 94, 117, 82, 72, 11
slavikrds [6]

Step-by-step explanation:

Using R, I used the following code to create a histogram:

bowling.scores <- c(87, 104, 79, 94, 117, 82, 72, 116, 105, 95, 88, 93, 109, 119, 75,  

                   103, 112, 97, 73, 85, 91, 86, 102, 99, 106, 84, 98, 83, 81, 96, 92)

data.frame(bowling.scores)

ggplot(data.frame(bowling.scores), aes(x=bowling.scores)) +  

 xlim(c(70, 120)) +

 scale_y_continuous(breaks = seq(0, 10, by=1), "Frequency") +

 geom_histogram(breaks=seq(70, 120, by=10), color="black", fill="grey60") +

 labs(title="Histogram of Bowling Scores", x="Bowling Scores", y="Frequency")

7 0
3 years ago
Please help 30 points
Ulleksa [173]

Replace x and y with the given values:

2(1/8 + 4) - (3/16*8)

Use distributive property:

1/4 + 8 - (3/16 * 8)

Simplify to get final answer:

8 1/4 - 1 1/2 = 6 3/4

4 0
3 years ago
Read 2 more answers
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