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Kryger [21]
3 years ago
5

A 13ft board is to be cut into three pieces, two equal length ones and the third 9in shorter than each of the other two. If cutt

ing does not result in any length being lost how long are the piecies
Mathematics
1 answer:
vaieri [72.5K]3 years ago
4 0

Answer:

The pieces are 55 inches, 55 inches and 46 inches long

Step-by-step explanation:

A 13ft board is to be cut into three pieces consisting of two equal length ones. The third one is 9in shorter than each of the other two.

Let us first convert the length of the board to inches:

1 ft = 12 inches

13 ft = 12 * 13 = 156 inches

Let the length of each of the other two pieces be x.

Therefore, the length of the third piece is (x - 9)

Therefore, the sum of the lengths of the three pieces is equal to 156 inches. This means that:

x + x + (x - 9) = 156

x + x + x - 9 = 156

=> 3x = 156 + 9

3x = 165

x = 165 / 3 = 55 inches

Each of the first two pieces are 55 inches long.

The length of the third piece will be:

55 - 9 = 46 inches

The pieces are 55 inches, 55 inches and 46 inches long.

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Which formula can be used to find the nth term of a geometric sequence where the fifth term is 1/6 and the common ratio is 1/4?
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Answer:

a_n = 16(\frac{1}{4})^{n - 1}

Step-by-step explanation:

Given:

Fifth term of a geometric sequence = \frac{1}{16}

Common ratio (r) = ¼

Required:

Formula for the nth term of the geometric sequence

Solution:

Step 1: find the first term of the sequence

Formula for nth term of a geometric sequence = ar^{n - 1}, where:

a = first term

r = common ratio = ¼

Thus, we are given the 5th term to be ¹/16, so n here = 5.

Input all these values into the formula to find a, the first term.

\frac{1}{16} = a*\frac{1}{4}^{5 - 1}

\frac{1}{16} = a*\frac{1}{4}^{4}

\frac{1}{16} = a*\frac{1}{256}

\frac{1}{16} = \frac{a}{256}

Cross multiply

1*256 = a*16

Divide both sides by 16

\frac{256}{16} = \frac{16a}{16}

16 = a

a = 16

Step 2: input the value of a and r to find the nth term formula of the sequence

nth term = ar^{n - 1}

nth term = 16*\frac{1}{4}^{n - 1}

a_n = 16(\frac{1}{4})^{n - 1}

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Answer:

  • a) T is not homogeneous
  • b) T is not additive
  • c) T is not homogeneous
  • d) T is not additive
  • e) T is not additive

Step-by-step explanation:

In each case there is an example where one property of linear functions fails.

  • a) T(2(1,0))=T((2,0))=(1,0); 2T((1,0))=2(1,0)=(2,0). These vectors are not equal, then T doesn't satisfy the condition of scalar multiplication (homogeneity).
  • b) T((1,2)+(2,3))=T(3,5)=(3,9); T((1,2))+T((2,3))=(1,1)+(2,4)=(3,5). Because these vectors are not equal, T doesn't satisfy the property of vector addition (additivity).
  • c) T(\frac{1}{2}(\pi,0))=T((\frac{\pi}{2},0))=(\sin(\frac{\pi}{2}),0)=(1,0); \frac{1}{2}T((\pi,0))=\frac{1}{2}(0,0)=(0,0) so T is not homogeneous.
  • d) T((-1,0)+(1,0))=T(0,0)=(0,0); T((-1,0))+T((1,0))=(1,0)+(1,0)=(2,0) then T is not additive.
  • e) T((0,0)+(1,0))=T(1,0)=(2,0); T((0,0))+T((1,0))=(1,0)+(2,0)=(3,0) then T is not additive.
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Answer:

I believe this is correct

A is FALSE

B is TRUE

C is FALSE

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