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lina2011 [118]
3 years ago
11

What are the main differences between the Greatest Common Factor and the Least Common Multiple of a pair of number? Use the numb

ers 10 and 15 to show the differences in finding the GCF and LCM. Explain your work.
Mathematics
2 answers:
Rina8888 [55]3 years ago
6 0

Answer:

isdk

Step-by-step explanation:

jekas [21]3 years ago
3 0

Answer:  GCF = 5    LCM = 30

<u>Step-by-step explanation:</u>

GCF is the biggest factor they have in common.

LCM is the smallest multiple they have in common.  This can be found by multiplying the GCF by the leftover values.

                                10                    15

                                ∧                      ∧

                             <u>2</u> · 5                  <u>3</u> · 5

GCF: 5

LCM: 5 · <u>2</u> · <u>3</u> = 30

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        +19    +19
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          x= 7
2. 4x + 12x = 6² + 4(11)
            16x = 36 + 44
            16x = 80
           ÷16   ÷16
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6 0
3 years ago
What is the joint relative frequency for 11th graders who want the break in the afternoon? Round to the nearest percent.
jek_recluse [69]
21%, looked up the answer!!
3 0
3 years ago
A buoy floating in the sea is bobbing in simple harmonic motion with period 2 seconds and amplitude 8 in. Its displacement d fro
Mrac [35]

Answer:

The equation of the displacement d as a function of time t is :

d(t)=8sin(\pi t+\pi )

Step-by-step explanation:

Generally , A simple harmonic wave is a sinusoidal function that is it can be expressed in simple sin or cos terms.

Thus,

d(t) = Asin(wt+c)

is the general form of displacement of a SHM.

where,

  • <em>d(t) is the displacement with respect to the mean position at any time t</em>
  • <em>A is amplitude </em>
  • <em>w is the natural frequency of oscillation (rads^{-1})</em>
  • <em>c is the phase angle which indicates the initial position of the object in SHM (rad)</em>

given,

  1. Time period (T) = 2s
  2. A=8
  3. The natural frequency (w) and time period (T) is :

                               w=\frac{2\pi} {T}

∴

w = \frac{2\pi }{2}  = \pi rads^{-1}

∴

the equation :

<em>⇒d(t)=8sin(\pi t+c)    </em>                    ------1

since d=0 when t=o ,

<em>⇒0=8sinc\\c=n\pi                         ------2</em>

where n is an integer ;

<u>⇒since the bouy immediately moves in the negative direction , x must be negative or c must be an odd multiple of \pi.</u>

<em>⇒ d(t) = 8sin(\pi t+(2k+1)\pi )         ------3</em>

where k is also an integer ;

the least value of k=0;

thus ,

the equation is :

d(t)=8sin(\pi t+\pi )

<em></em>

7 0
3 years ago
A rectangle has an area of 40 sq units , then length is 6 units greater than the width
devlian [24]

Answer:

A=L*W

Let w be width

L=(w+6)

40=(w+6)*w

40= w^{2} +6w

w^{2} +6w-40=0

w^{2}+10w-4w-40=0  

w(w+10)-4(w+10)=0

(w-4)(w+10)=0

w=4

Length= 10 units

Width=4 units

Step-by-step explanation:

6 0
3 years ago
In the figure, GK bisects FGH
bija089 [108]

Answer:

w = 7

Step-by-step explanation:

Given:

m<FGK = (7w + 3)°

m<FGH = 104°

angle bisector of <FGH = GK

Required:

Value of w

SOLUTION:

Since GK bisects angle FGH, it divides the angle into two equal parts. Therefore, the following equation can be generated to find the value of w:

m<FGH = 2*m<FGK

104 = 2*(7w + 3) (substitution)

Divide both sides by 2

\frac{104}{2} = \frac{2*(7w + 3)}{2}

52 = 7w + 3

Subtract 3 from each side

52 - 3 = 7w + 3 - 3

49 = 7w

Divide both sides by 7

\frac{49}{7} = \frac{7w}{7}

7 = w

w = 7

8 0
3 years ago
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