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Alinara [238K]
3 years ago
9

x P(x) 0 0.25 1 0.3 2 0.1 3 0.35 Find the standard deviation of this probability distribution. Give your answer to at least 2 de

cimal places
Mathematics
1 answer:
barxatty [35]3 years ago
6 0

Answer:

The standard deviation of this probability distribution is 1.2.

Step-by-step explanation:

We have that:

P(X = 0) = 0.25

P(X = 1) = 0.3

P(X = 2) = 0.1

P(X = 3) = 0.35

Mean:

Each value multiplied by its probability. So

M = 0*0.25 + 1*0.3 + 2*0.1 + 3*0.35 = 1.55

Variance:

Sum of the squares of the values subtracted from the mean, and multiplied by its probability.

V = 0.25*(0-1.55)^2 + 0.3*(1-1.55)^2 + 0.1*(2-1.55)^2 + 0.35*(3-1.55)^2 = 1.4475

Standard deviation:

Square root of the variance. So

S = \sqrt{V} = \sqrt{1.4475} = 1.2

The standard deviation of this probability distribution is 1.2.

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