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alexdok [17]
3 years ago
7

ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions

.

Mathematics
1 answer:
Elina [12.6K]3 years ago
3 0

Answer:

\boxed{3x-5y}

Step-by-step explanation:

=> 9x^2-25y^2

Let's factor it out

=> (3x^2)-(5y)^2

Using Formula a^2-b^2 = (a+b)(a-b)

=> (3x-5y)(3x+5y)

So, (3x-5y) is one of the factor of it!

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Sylvie finds the solution to the system of equations by graphing.
Taya2010 [7]

Answer:

The solution is at (-0.5,0.5).

Step-by-step explanation:

I graphed both equations on the graph below to show you where the solution of the system is.

4 0
3 years ago
Which is an equation of the line that
Alex Ar [27]
Answer; D) y=-3x+13
4 0
3 years ago
A group of 6p people are renting a vacation house together the price of the rental is 3p to the 2nd power if they split the cost
Tanya [424]
So we just do
cost/number of people=cost per 1 person
so
(6p)/(3p^2)
remember that you can split it up and make ones
\frac{6p}{3p^{2}}=\frac{6}{3p} times \frac{p}{p}=\frac{2}{1p} times \frac{p}{p} times \frac{3}{3}=\frac{2}{1p}  times 1 times 1=2/p

easy way is
remember that
(x^m)/(x^n)=x^(m-n)
so
(6p)(3p^2)=6/(3p=2/p=2p^-1


each member pays 2/p

4 0
3 years ago
A car costs$cents when new. It was sold for four fifths of its cost price. How much money was lost on the car.
REY [17]

The question is incomplete as the cost price isn't given. However, taking the cost price as x :

Answer:

Kindly check explanation

Step-by-step explanation:

Given :

A car costs$cents when new. It was sold for four fifths of its cost price. How much money was lost on the car.

Let :

Cost price when new = x

Cost price when sold = 4/5 * cost price when new

Cost when sold = 4/5 of x = 4x/5

Amount of money lost on the car = (Cost price of car when new - Cost of car when sold)

Hence,

Amount of money lost on the car = (x - 4x/5)

x - 4x/5 = (5x - 4x) / 5 = x / 5

To obtain the exact price, kindly input the omitted cost when new for x.

7 0
2 years ago
Please help
Montano1993 [528]

Answer:

M = 2x² - (ax/3) + by

B = - 3x²y + (xy³/3) - cy

Step-by-step explanation:

Equation 1 is

2x² - (1/3)ax + by - M = 0

M = 2x² - (ax/3) + by

Equation 2

3x²y - (1/3)xy³ + cy + B = 0

B = - 3x²y + (xy³/3) - cy

Hope this Helps!!!

7 0
3 years ago
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