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balu736 [363]
4 years ago
7

Suppose that PR=47. Solve for x and find the lengths of PQ, and QR.

Mathematics
1 answer:
lidiya [134]4 years ago
6 0

Answer:

x = 10

PQ = 27

QR = 20

Step-by-step explanation:

You can add up PQ and QR and set it equal to PR.  Solve for x.

(2x + 7) + (2x) = 47

2x + 7 + 2x = 47

4x + 7 = 47

(4x + 7) - 7 = 47 - 7

4x = 40

4x/4 = 40/4

x = 10

Now, use the solved x-value to find PQ and QR.

PQ = 2x + 7

PQ = 2(10) + 7

PQ = 20 + 7

PQ = 27

QR = 2x

QR = 2(10)

QR = 20

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Did I get this right?
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Find the area of the shaded region
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Answer:  21.994 cm²

Step-by-step explanation:

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3 years ago
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