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Lana71 [14]
2 years ago
12

Tam has picked up 5 different books that interest

Mathematics
2 answers:
Ostrovityanka [42]2 years ago
4 0

Answer:

ujn uzun g ne bu bu http TV fy ve g CD ve de c TT vcxcxc TR TRT TT ttgrsxfgzfggfxvzgrstgygfdfdzvsdcvzdcgz TR

Serggg [28]2 years ago
3 0
He checks out 2 different types it’s wrong I know the answer but I don’t help so xx
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A gene carries the______ for a trait.
MrRissso [65]

Answer:

A gene carries the <u>information</u> for a trait.

Step-by-step explanation:

Just got it right on edge

8 0
3 years ago
What is 5/2 - 1/3 = 1/3y
kati45 [8]

5/2 - 1/3 = 1/3y

I would convert the denominators to 6 to make this easier like this

15/6 - 2/6 = 2/6y

Now you can subtract easily like so

13/6 = 2/6y

Now divide

y = 13/6 divided by 2/6

To divide fractions do keep (numbers) change (sign) and flip (numbers)

y = 13/6 x 6/2

Now multiply:

78/12 = 6 1/2 = 6.5

y = 6.5 is your final answer!

5 0
3 years ago
Please help I need the equation for it
MissTica

simply need to fill in Y=Mx+b!

slope is 1/2, the and b (the y intercept) is 0! so y=1/2x + 0 or y=1/2x :)

5 0
2 years ago
In November, the rain in a certain valley tends to fall in storms of several days duration. The unconditional probability of rai
Mumz [18]

Answer:

0.0594 = 5.94% probability of rain on November 1 and 2, but not on November 3.​

Step-by-step explanation:

Rain on November 1:

0.9 of 0.6(rain on Oct 31).

0.3 of 0.4(not rain on Oct 31).

Rain on November 2:

Considering rain on November 1, 0.9 probability of rain.

Rain on November 3:

Considering rain on November 2, 0.1 probability of rain.

Find the probability of rain on November 1 and 2, but not on November 3.​

Multiplicating the probabilities:

p = (0.9*0.6+0.3*0.4)*0.9*0.1 = 0.0594

0.0594 = 5.94% probability of rain on November 1 and 2, but not on November 3.​

4 0
3 years ago
You deposit $50 in your savings account. One week later, you withdraw $20. Write each amount as an integer.
77julia77 [94]

you add +50 dollars in ur account then -20

3 0
3 years ago
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