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Neporo4naja [7]
3 years ago
14

Ten qualified applicants apply for a part-time job. If the manager randomly hires 3 of them, what is the probability that he hir

es the 3 youngest?
Mathematics
1 answer:
hram777 [196]3 years ago
7 0
3/30 (I think) they have a 1/10 of picking the youngest, so that times three
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Will give brainliest!
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Y=-6-x is not equal to 2x+y=12. Both sides were not divided by two when it was simplified.
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Given that NML is similar to SQR, what is x?<br><br> a) x=18<br> b) x=14.2<br> c) x=40.5<br> d) x=24
Anni [7]

a) x=18

16÷24 = 2/3

2/3 × 27=18

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3 years ago
Anaika has found 25 coins this week, all quarters and dimes . If total worth of all coins is $4.00, how many of each coin does a
balu736 [363]

Answer:

10 quarters and 15 dimes

Step-by-step explanation:

25 = Quarters +  Dimes

Total worth = $4.00 =  0.25* Quarter +  0.1*Dimes

so...

25 = Q + D ,     D = 25 - Q

4 =  0.25*Q + 0.1 * (25 - Q)

4 = 0.25 * Q + 2.5 - 0.1*Q

1.5 = 0.15Q

Q = 10

D = 15

4 0
3 years ago
The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.
mote1985 [20]

The confidence interval for the mean usage of water is (18.7,20.5).

Given population standard deviation of 2.4, mean of 19.5 gallons per day and confidence interval of 98%.

We have to find the confidence interval for the mean usage of water.

To find out the confidence interval we have to first find margin of error.

μ=19.5

σ=2.4

α=0.98

α/2=0.49

We have to find the z value for the p value 0.49 which is z=2.33

Margin of error=z*μ/\sqrt{n}

=2.33*19.5/\sqrt{3034}

=0.82

lower level=mean -m

=19.5-0.82

=18.68

after rounding upto 1 decimal

=18.7

upper mean = mean+m

=19.5+0.82

=20.52

Hence the confidence interval for the usage of water is (18.7,20.52).

Learn more about margin of error at brainly.com/question/10218601

#SPJ4

7 0
2 years ago
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