The left-handed students12% are left handed, percent means per hundred. Change percent into per 100.
12% =

Then simplify the fraction by dividing the numerator and denominator by 4

=

=

This is the fraction showing the proportion of the left-handed students
The right-handed studentsDetermine the fraction showing the proportion of the right-handed students
1 - the left-handed
= 1 -

Equalize the denominator to 25

Simplify

This is the proportion of the right-handed students
<span>
Are there more right-handed or left-handed students?There are more right-handed students than the left-handed students, because 21/25 is more than 3/25</span>
Answer:
The series is absolutely convergent.
Step-by-step explanation:
By ratio test, we find the limit as n approaches infinity of
|[a_(n+1)]/a_n|
a_n = (-1)^(n - 1).(3^n)/(2^n.n^3)
a_(n+1) = (-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)
[a_(n+1)]/a_n = [(-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)] × [(2^n.n^3)/(-1)^(n - 1).(3^n)]
= |-3n³/2(n+1)³|
= 3n³/2(n+1)³
= (3/2)[1/(1 + 1/n)³]
Now, we take the limit of (3/2)[1/(1 + 1/n)³] as n approaches infinity
= (3/2)limit of [1/(1 + 1/n)³] as n approaches infinity
= 3/2 × 1
= 3/2
The series is therefore, absolutely convergent, and the limit is 3/2
4.125 x 14 = 57.75
So 57.75 is the answer and I have to show my work
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