The one in the hundred thousands place blake the vaule of the middle one

Analyze the diagram below and complete the instructions that follow.

Alona [7]

A

Durhsvsn its a I try

6 0

3 years ago

Which applies the power of a product rule to simplify (5 t) cubed?

Elena L [17]

Answer:

(5 t ) cubed = 5 cubed . t cubed = 125 t cubed applies the power of a product rule to simplify (5 t) cubed ⇒ 3rd answer

Step-by-step explanation:

Let us revise some rules of exponents

$a^{m}$ × $a^{n}$ = $a^{m+n}$

$a^{m}$ ×÷ $a^{n}$ = $a^{m-n}$

$(a^{m})^{n}$ = $a^{m.n}$

$(a.b)^{m}$ = $a^{m}$ . $b^{m}$

To simplify $(5t)^{3}$

∵ 5t means 5 × t

∵ Both of them are cubed

- Use the 4th rule above

∴ $(5t)^{3}$ = $(5)^{3}.(t)^{3}$

∵ (5)³ = 5 × 5 × 5 = 125

∴ $(5t)^{3}$ = $(5)^{3}.(t)^{3}$ = 125 t³

(5 t ) cubed = 5 cubed . t cubed = 125 t cubed applies the power of a product rule to simplify (5 t) cubed

3 0

3 years ago

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21) There are 35 people going to a museum. Each ticket costs $20. What is the

Bas_tet [7]

35 x 20 dollars= 700 dollars. Total cost of all tickets equals 700 dollars

4 0

3 years ago

An experiment to investigate the survival time in hours of an electronic component consists of placing the parts in a test cell

mixer [17]

Answer:

a) The sample mean is of 49 and the sample standard deviation is of 11.7.

b) The range of the true mean at 90% confidence level is of 9.62 hours.

c) The prediction interval, at a 90% confidence level, of it's failure time is between 39.38 hours and 58.62 hours.

Step-by-step explanation:

Question a:

Sample mean:

$\overline{x} = \frac{34+40+46+49+61+64}{6} = 49$

Sample standard deviation:

$s = sqrt{\frac{(34-49)^2+(40-49)^2+(46-49)^2+(49-49)^2+(61-49)^2+(64-49)^2}{5}} = 11.7$

The sample mean is of 49 and the sample standard deviation is of 11.7.

b)Determine the range of the true mean at 90% confidence level.

We have to find the margin of error of the confidence interval. Since we have the standard deviation for the sample, the t-distribution is used.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.9}{2} = 0.95$ . So we have T = 2.0.150

The margin of error is:

$M = T\frac{s}{\sqrt{n}}$

In which s is the standard deviation of the sample and n is the size of the sample. So

$M = 2.0150\frac{11.7}{\sqrt{6}} = 9.62$

The range of the true mean at 90% confidence level is of 9.62 hours.

(c)If a seventh sample is tested, what is the prediction interval (90% confidence level) of its failure time.

This is the confidence interval, so:

The lower end of the interval is the sample mean subtracted by M. So it is 49 - 9.62 = 39.38 hours.

The upper end of the interval is the sample mean added to M. So it is 49 + 9.62 = 58.62 hours.

The prediction interval, at a 90% confidence level, of it's failure time is between 39.38 hours and 58.62 hours.

4 0

3 years ago

If g + 11 = 16, then evaluate 5g + 12

mote1985 [20]

Answer:

37

Step-by-step explanation:

g= 5 because 11+5 = 16

so 5*5 is 25 + 12 would equal 37

5 0

3 years ago

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