The one in the hundred thousands place blake the vaule of the middle one

HELP ME PLEASE !!!!!!!!!

Kay [80]

Answer: 33 333,33 per month or 400 000 per year

Step-by-step explanation:

You need 48 000 + 0.035X = 62 000

So ( 62 000 - 48 000 ) / 0.035 = X

Then you can divide X per 12 (months in a year)

And you have your answer per month .

So 33 333,33 total sale per month to have at least as high as the average pay

5 0

2 years ago

Draw and label a tape diagram to subtract 10, 20, 30

Svet_ta [14]

This isnt something I can do... But draw and label a tape diagram that goes from 0 to 30.

8 0

3 years ago

Help me I’m on gradpoint. I will mark you brainlest if you can also find the website to get all gradpoint answers!

AlekseyPX

Answer:

C. (1, 1, 2)

Step-by-step explanation:

Well plugging them in one by one.

x + y - z = 0

-1 + 2 - 4 = 0

no.... no it doesn't equal 0 so it isn't the solution

-1 + 0 - 2 = 0

nope it doesn't equal 0 so it's also not the solution

1 + 1 - 2 = 0

Yes! this could equal the solution so lets keep going down the line

3x - y + z = 4

(3*1) -1 + 2 = 4

Yes! this also is correct

I could keep talking and talking but yes, (1, 1, 2) is your answer

Hope this helps! <3

3 0

2 years ago

businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message

KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let X = number of text messages receive or send in an hour.

The random variable X follows a Poisson distribution with parameter λ.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: $\lambda=\frac{62.7}{24}= 2.6125$ .

The probability of a random variable can be computed using the formula:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...$

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

$P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180$

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

$=1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667$

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0

3 years ago

Each day in Bio 18, Derek leaves a stack of paper packets near the entry door for students to obtain. Eighty-one percent of stud

Rainbow [258]

Answer:

Step-by-step explanation:

This is a binomial probability distribution because there are only 2 possible outcomes. It is either a randomly selected student grabs a packet before being seated or the student sits first before grabbing a packet. The probability of success, p in this scenario would be that a randomly selected student sits first before grabbing a packet. Therefore,

p = 1 - 0.81 = 0.91

n = 9 students

x = number of success = 3

The probability that exactly two students sit first before grabbing a packet, P(x = 2) would be determined from the binomial probability distribution calculator. Therefore,

P(x = 2) = 0.297

5 0

3 years ago