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3 years ago

I’m not sure what the answer is

Mathematics

1 answer:

mr Goodwill [35]3 years ago

6 0

Answer:

I want to say 96

Step-by-step explanation:

because that kinda looks like a right angle but just a tad bigger

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What are the steps for solving and graphing 2x - 3y = 9?<br><br> please help!

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Step-by-step explanation:

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3 years ago

Jasmine is trying to replace the flooring in her rectangular bedroom. When she measured the width and length of the floor, she f

maks197457 [2]

By finding the area of the rectangle, we will see that she will need 150 ft^2 of flooring.

<h3>How to get the area of the rectangle?</h3>

For a rectangle of length L and width W, the area is:

A = L*W

And the perimeter is:

P = 2*(L + W).

In this case, we know that the length is 5ft longer than the width, so we can write:

L = W + 5ft

We also know that the perimeter is 50ft, so we can write:

P = 50ft = 2*(W + 5ft + W)

50ft = 4*W + 10ft

40ft/4 = W = 10ft

So the width is 10 ft, and then the length will be:

L = 10ft + 5ft = 15ft

So the area of the rectangle is:

A = 10ft*15ft = 150 ft^2

She will need 150 ft^2 of flooring.

If you want to learn more about areas, you can read:

brainly.com/question/24487155

4 0

2 years ago

It took a fish 0.6 second to reach to 1.5 feet below sea level from the surface. How many feet per second did the fish descend d

Trava [24]

Answer:

2.5 ft/sec

Step-by-step explanation:

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3 years ago

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The length of a diagonal of a quadrilateral shaped field Is 48 m And the length of perpendicular dropped on it from the remainin

olchik [2.2K]

Answer:

$1008\text{ m}^2$

Step by step explanation:

Please find the attachment.

We have been given that the length of a diagonal of a quadrilateral shaped field Is 48 m. The length of perpendicular dropped on it from the remaining apposite vertices are 16 m and 26 m.

We can see from our attachment that diagonal AC divides our quadrilateral field into two triangular fields and AC will be the base of both triangles.

To find the area of our given quadrilateral we will find the areas of both triangles and add the areas.

Let us find area of triangle ABC with base 48 m and height 26 m.

$\text{Area of triangle}=\frac{1}{2}(\text{ Base}\times\text{ Height})$

$\text{Area of triangle ABC}=\frac{1}{2}\times 48\times 26$

$\text{Area of triangle ABC}=24\times 26$

$\text{Area of triangle ABC}=624$

Therefore, the area of triangle ABC will be 624 square meters.

Now let us find area of triangle ADC with base 48 m and height 16 m.

$\text{Area of triangle ADC}=\frac{1}{2}\times 48\times 16$

$\text{Area of triangle ADC}=24\times 16$

$\text{Area of triangle ADC}=384$

Therefore, the area of triangle ADC will be 384 square meters.

Now let us add areas of triangles ABC and ADC to get the area of our quadrilateral ABCD.

$\text{Area of quadrilateral ABCD}=384+624$

$\text{Area of quadrilateral ABCD}=1008$

Therefore, the area of quadrilateral shaped field will be 1008 square meters.

6 0

4 years ago

Can you please just do number 6 thats the only one I need.

Pie

Answer:

it is C.

Step-by-step explanation:

8 0

3 years ago

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