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Orlov [11]
3 years ago
9

I’m not sure what the answer is

Mathematics
1 answer:
mr Goodwill [35]3 years ago
6 0

Answer:

I want to say 96

Step-by-step explanation:

because that kinda looks like a right angle but just a tad bigger

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Please help anybody I need to fast please
elena55 [62]
Answer:
D. t = -1

step-by-step explanation:
that side should be 180 degrees and the whole is 360 but we are only measuring half
so (20t + 5) = 15t
-20t -20t
5 = -5t
/-5 /-5
-1 = t
4 0
3 years ago
". How many half times do they have in football?<br> A.1 B.3 C.None ?
NARA [144]

Answer:

A. 1

Step-by-step explanation:

In each football game there is only 1 halftime

5 0
3 years ago
The outside temperature at midnight today in Polina's hometown was 18 degrees Fahrenheit. The temperature increases by 1.2 degre
densk [106]

Answer:

only students who have recess at 12 p.m. or later may go out

Step-by-step explanation:

Let the time after midnight be represented by t, and the temperature be y. Since the temperature increases by 1.2 degrees Fahrenheit each hour, the time taken to reach 32 degrees Fahrenheit can be gotten from:

y = 1.2t + 18

put y = 32

32 = 1.2t + 18

1.2t = 14

t = 14/1.2 = 11.67 hours

Since the recess starts at half hour or hour, hence the recess would start at t = 12 hours, i.e. at 12 p.m.

Hence only students who have recess at 12 p.m. or later may go out

4 0
3 years ago
Plzz help!!!! I'm giving 35 points for the question on my profile (You pick a card at random...) If you answer you can type some
leonid [27]

Answer:

Thanks.

Step-by-step explanation:

4 0
3 years ago
Find the total force on a piston of diameter 3.25 in., if the pressure (P) exerted on it is 150 lb/sq.In. Use 3.14 for and round
skelet666 [1.2K]

Answer:

1244 Ibf(Pounds force)

Step-by-step explanation:

The formula for Total force on a piston when given the diameter of the bore area =

F = P × π × d²/4

P = 150 lb/sq.In

π = 3.14

d = 3.25 in

Hence,

F = 150 lb/sq.In × 3.14 × 3.25 in /4

= 4974.9375 ÷ 4

= 1243.734375 Ibf(Pounds force)

Approximately = 1244 Ibf(Pounds force)

6 0
3 years ago
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