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3 years ago

What are the domain and range of the function below?

Mathematics

2 answers:

jekas [21]3 years ago

6 0

Answer:

Domain: all real numbers

Range: all real numbers greater than or equal to -2

Step-by-step explanation:

The domain is the set of x-coordinates.

It is the set of real numbers since x can be any real number.

The range is the set of y-coordinates.

The minimum value for y is -2. y can be -2 or any real number greater than -2.

Answer:

Domain: all real numbers

Range: all real numbers greater than or equal to -2

musickatia [10]3 years ago

5 0

Answer:

C on Edge

Step-by-step explanation:

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Find the slope of the line through

Dafna11 [192]

When finding the slope between two points, we simply take (y2-y1) / (x2-x1)
For this, we can substitute the following to get this :
y2-y1 and x2-x1
1 - 4 and 7 - 1
-3 and 6
-3 / 6 gets you -1/2

Therefore the answer is :
The slope of the line is -1/2

4 0

1 year ago

THIS IS SO CONFUSING! I hate this

djyliett [7]

Answer:

2 and 6 for the circles.

-18 for the square.

Step-by-step explanation:

-3 times a number is -6.

$-3 \times 2 = -6$

The number is 2.

2 times a number is 12.

$2 \times 6 = 12$

The number is 6.

6 times -3.

$6 \times -3 = -18$

The number is -18.

3 0

2 years ago

How do I find x in this problem?

torisob [31]

Answer:

(6-2)×180 = 720

101+154+72+123+145+x=720

595 + x = 720

x = 720-595

x= 125

5 0

2 years ago

Za and Zb are complementary angles. Za measures 78º.<br> What is the measure of Zb?

meriva

Answer:‍♀️

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Please help radical expression dividing

77julia77 [94]

$\bf \cfrac{\sqrt[4]{63}}{4\sqrt[4]{6}}\qquad 
\begin{cases}
63=3\cdot 3\cdot 7\\
6=2\cdot 3
\end{cases}\implies \cfrac{\sqrt[4]{3\cdot 3\cdot 7}}{4\sqrt[4]{2\cdot 3}}\implies \cfrac{\underline{\sqrt[4]{3}}\cdot \sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}\cdot \underline{\sqrt[4]{3}}}
\\\\\\
\cfrac{\sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{3\cdot 7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}$

$\bf \textit{now, rationalizing the denominator}\\\\
\cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}\cdot \cfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21}\cdot \sqrt[4]{8}}{4\sqrt[4]{2}\cdot \sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21\cdot 8}}{4\sqrt[4]{2\cdot 2^3}}\implies \cfrac{\sqrt[4]{168}}{4\sqrt[4]{2^4}}
\\\\\\
\cfrac{\sqrt[4]{168}}{4\cdot 2}\implies \cfrac{\sqrt[4]{168}}{8}$

and is all you can simplify from it.

so... all we did, was rationaliize it, namely, "getting rid of the pesky radical at the bottom", we do so by simply multiplying it by something that will raise the radicand, to the same degree as the root, thus the radicand comes out.

6 0

3 years ago