3 years ago

Find the nth derivative of (sin x)^3

1 answer:

5 0

You'll need to try to find the pattern that applies here. Find the 1st, 2nd, 3rd, 4th and 5th derivatives. Is a pattern evident?

n=1: first derivative of (sin x)^3 is 3(sin x)^2*cos x (which is a product)

n=2: second deriv. of (sin x)^3 is 3(sin x)^2*(-sin x) + (cos x)*(6sin x cos x)

Please find the 3rd, 4th and 5th derivatives. Then try to recognize a pattern in the derivatives governed by the counter "n".

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PLEASE HELP, WILL GIVE BRAINLIEST FOR RIGHT ANSWER!

Zarrin [17]

Answer:

Y = 2/3x-8/3

Step-by-step explanation:

y − 4 = 2/3 ( x − 3)

y − 4 = 2/3x -2

y = 2/3x +2

~~~~~~~~~~~~~~~~~

-2 = 2/3(1) + b

b = -2 2/3 = -8/3

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3 years ago

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stich3 [128]

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3 years ago

The functions f(x) and g(x) are described below: f(x) = 7x + 9 g(x) = 7x −4 The graph of g(x) is obtained by shifting down the g

Slav-nsk [51]

Correct Answer:
Option A

Solution:

f(x) = 7x + 9
g(x) = 7x - 4

We can re-write g(x) as:

g(x) = 7x + 9 - 13

Since 7x+9 is equal to f(x), we can write:

g(x) = f(x) - 13

This relation shows that g(x) is obtained by shifting f(x) 13 units vertically down. So the correct answer is option A.

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4 years ago

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FromTheMoon [43]

Answer:

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Step-by-step explanation:

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3 years ago

If every student got one vote, but there were 25 students absent on the day of the vote, how many

kherson [118]

Answer:

Not enough information.

Step-by-step explanation:

The 25 students absent is irrelevant. We still don't know the total number of students at Riverside Elementary School.

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