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3 years ago

How many 3-digit passwords can be formed from the digits 0 through 9

1 answer:

3 0

Answers 729 900 1,000
This is asking "how many numbers are there from 0 to 999 ? " :)
(remember to include 0)
They want all the passwords from 000 through 999 So that's 10 choices for each of the three places. 10^3 = 1000. :) or just list them all 000 001 002 003 ... 997 998 999 Which is 1,000 total codes.

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On the number line below, the letters a and b are the same distance from 0. What is a + b?

jolli1 [7]

Answer:

The answer here would be 0.

Step-by-step explanation:

If a and b are both equal distances from 0, then adding the together would equal 0. Since a is the inverse of b, using any number and its inverse will show you why the answer is 0. For example, if b is 9 then a would be -9. Adding these together equals 0.

5 0

4 years ago

Giving 100 points.

Nitella [24]

Answer:

1. Cost per customer: 10 + x

Average number of customers: 16 - 2x

$\textsf{2.} \quad -2x^2-4x+160\geq 130$

3. $10, $11, $12 and $13

Step-by-step explanation:

Given information:

$10 = cost of buffet per customer
16 customers choose the buffet per hour
Every $1 increase in the cost of the buffet = loss of 2 customers per hour
$130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

Part 1

Cost per customer: 10 + x

Average number of customers: 16 - 2x

Part 2

The cost per customer multiplied by the number of customers needs to be at least $130. Therefore, we can use the expressions found in part 1 to write the inequality:

$(10 + x)(16 - 2x)\geq 130$

$\implies 160-20x+16x-2x^2\geq 130$

$\implies -2x^2-4x+160\geq 130$

Part 3

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

$\implies -2x^2-4x+160\geq 130$

$\implies -2x^2-4x+30\geq 0$

$\implies -2(x^2+2x-15)\geq 0$

$\implies x^2+2x-15\leq 0$

$\implies (x-3)(x+5)\leq 0$

Find the roots by equating to zero:

$\implies (x-3)(x+5)=0$

$x-3=0 \implies x=3$

$x+5=0 \implies x=-5$

Therefore, the roots are x = 3 and x = -5.

Test the roots by choosing a value between the roots and substituting it into the original inequality:

$\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144$

As 144 ≥ 130, the solution to the inequality is between the roots:

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an increase in cost. It does not confirm that if the cost is reduced (less than $10) the number of customers increases per hour.]

Cost per customer:

$x =0 \implies 10 + 0=\$10$

$x=3 \implies 10+3=\$13$

Therefore, the possible buffet prices Noah could charge are:

$10, $11, $12 and $13.

8 0

2 years ago

Please help me solve this step by step please!!

qaws [65]

Answer:

7^(1-3+1) = 7^-3

Step-by-step explanation:

Here is the rule you should know: when multiplying powers of the same base you add the exponents ans when dividing powers of the same base you subtract the exponents.

Also, if there is no number at the exponent, it is 1.

4 0

3 years ago

Read 2 more answers

Given that f(x)=2x+1 and g(x)=-5x+2 slice for f(g(x)) when x=3?

mezya [45]

Answer:

x = -25.

Step-by-step explanation:

If f(x) = 2x + 1, and g(x) = -5x + 2, then f(g(x)) = 2(-5x + 2) + 1 = -10x + 4 + 1 = -10x + 5.

f(g(x)) = -10x + 5, and x = 3.

-10 * 3 + 5

= -30 + 5

= -25.

Hope this helps!

3 0

3 years ago

Brian pays £275.23 a year on his car insurance.

Roman55 [17]

Hope this helps!!!!!!!!!!

5 0

3 years ago