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aalyn [17]
4 years ago
11

You need to buy fertilizer for a circular flower bed with a diameter

Mathematics
1 answer:
PSYCHO15rus [73]4 years ago
7 0

14 bags of fertilizer are needed

<em><u>Solution:</u></em>

Given that You need to buy fertilizer for a circular flower bed with a diameter

of 13 feet

Diameter = 13 feet

radius = \frac{diameter}{2}

radius = \frac{13}{2} = 6.5

Therefore radius of circular flower bed is 6.5 feet

<em><u>Area of circle is given as:</u></em>

\text{ area of circle } = \pi r^2

Substitute r = 6.5

\text{ area of circle } = 3.14 \times 6.5^2 = 132.665

Given that one bag will fertilize 10 square feet

1 bag = 10 square feet

Then number of bags needed are:

\rightarrow \frac{132.665}{10} = 13.2665

Thus approximately 14 bags of fertilizer are needed

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Find the quotient of quantity of 4 times x to the 3rd power minus 12 times x to the 2nd power plus 8 times x all over negative 4
Readme [11.4K]

\displaystyle \frac{4x^3-12x^2+8x}{-4x}=\frac{4x^3}{-4x}+\frac{-12x^2}{-4x}+\frac{8x}{-4x}\\\\=-x^2+3x-2

This result corresponds to the first selection.

5 0
4 years ago
the breadth of a rectangular plot is 20 m less than its lengths find its dimensions if its perimeter is 120​
tangare [24]

Answer:

breadth = 25m

length= 35m

Step-by-step explanation:

perimeter is distance all round a figure

in a rectangle we have two pairs of  opposite but equal lines

breadth = 2x( because of the two breadths in a rectangle) - 20

length = 2x(  because of the two lengths in a rectangle)

perimeter = 2x + 2x - 20

120 = 4x - 20

120 + 20 = 4x

140 = 4x

35 = x

to get the dimensions, we have to divide by 2 as we took both parts of each dimension

breadth =<u> 2x - 20</u>

                     2

             <u>=2(35) - 20</u>

                      2

              <u>= 70 - 20</u>

                      2

              <u>= 50m</u>

                   2

               = <u>25m</u>

length =<u> 2x</u>

              2

        <u>= 2(35)</u>

              2

        <u> = 70m</u>

              2

           = <u>35m</u>

<u />

4 0
3 years ago
A tile store charges $607.50 to install 135 square feet of tile. Assuming they charge the same rate
jasenka [17]

Answer:

the tile is 4.50 per square foot to install

it will cost 3780.00 to install 840 square feet

Step-by-step explanation:

divide 607.50 by 135 to find out the price per square foot to install

multiply the price per square foot by the number of square feet you are installing so 4.50 X 840

7 0
4 years ago
Can someone answer this please
Gwar [14]

Answer:

The coordinates of point P are (1, -1)

Step-by-step explanation:

  • If the point (x, y) reflected about the x-axis, then its image is (x, -y)
  • To find the image of a point reflected about the x-axis change the sign of its y-coordinate
  • The rule is R x-axis → (x, -y)

  • If the point (x, y) reflected about the y-axis, then its image is (-x, y)
  • To find the image of a point reflected about the y-axis change the sign of its x-coordinate
  • The rule is R y-axis → (-x, y)

→ Assume that the coordinates of point P are (x, y)

∵ The coordinates of point P are (x, y)

∵ The rule of the reflection is R y-axis (P)

∴ Its image = (-x, y)

∵ The image = (-1, -1)

→ Equate the two images

∴ (-x, y) = (-1, -1)

∴ -x = -1

→ Divide both sides by -1

∴ x = 1

∵ y = -1

∴ The coordinates of point P are (1, -1)

4 0
3 years ago
Use the definition of continuity and the properties of limits to show that the function f(x)=x sqrtx/(x-6)^2 is continuous at x
qaws [65]

Answer:

The function is  continuous at  x = 36

Step-by-step explanation:

From the question we are told that

      The  function is f(x)  =  x *  \sqrt{ \frac{x}{ (x-6) ^2 }  }  

       The  point at which continuity is tested is  x =  1

Now from the definition  of continuity ,

   At function is continuous at  k if  only  

       \lim_{x \to k}f(x)  =  f(k)

So

      \lim_{x \to 36}f(x)  =  \lim_{n \to 36}[x *  \sqrt{ \frac{x}{ (x-6) ^2 }  }]

                            = 36 *  \sqrt{ \frac{36}{ (36-6) ^2 }  }

                             = 7.2

Now  

     f(36) = 36  *  \sqrt{ \frac{36}{ (36-6) ^2 }  }

     f(36) = 7.2

So  the given function is continuous at  x =  36

because

          \lim_{x \to 36}f(x)  =  f(36)

7 0
3 years ago
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