Question

Find the quotient of quantity of 4 times x to the 3rd power minus 12 times x to the 2nd power plus 8 times x all over negative 4 times x. −x2 + 3x − 2 x2 − 12x + 4 −x2 − 3x + 2 x2 + 12x − 4

Answer 1

$\displaystyle \frac{4x^3-12x^2+8x}{-4x}=\frac{4x^3}{-4x}+\frac{-12x^2}{-4x}+\frac{8x}{-4x}\\\\=-x^2+3x-2$

This result corresponds to the first selection.