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Ann [662]
3 years ago
9

There are 7 7/8 cups of skittles in a Jar. If 2 1/4 cups are used for a party, how many skittes are left in the jar?

Mathematics
1 answer:
maw [93]3 years ago
4 0
2 1/4 = 2 2/8. So, simply subtract 7 7/8 - 2 2/8 to get your final answer of 5 5/8
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The area of the base of a rectangular prisim four and three fourths and the height of two and one third what is the volume
VikaD [51]
Data:
A_{base} = 4 \frac{3}{4} = \frac{4*4+3}{4} = \frac{16+3}{4} \to A_{base} = \frac{19}{4}

h (height) = 2 \frac{1}{3} =  \frac{3*2+1}{3} = \frac{6+1}{3} \to h (height) = \frac{7}{3}
v (volume) = ?

Formula: V =  A_{b}*h

Solving:
V = A_{b}*h
V =  \frac{19}{4} * \frac{7}{3}
V =  \frac{133}{12}
V = 11.08333....
\boxed{\boxed{V \approx 11.08}}\end{array}}\qquad\quad\checkmark
7 0
4 years ago
A student wanted to construct a 95% confidence interval for the average age of students in her statistics class. She randomly se
Darina [25.2K]

Answer: (17.42, 20.78)

Step-by-step explanation:

As per given , we have

Sample size : n= 9

\overline{x}=19.1 years

Population standard deviation is not given , so it follows t-distribution.

Sample standard deviation : s= 1.5 years

Confidence level : 99% or 0.99

Significance level : \alpha= 1-0.99=0.01

Degree of freedom : df= 8  (∵df =n-1)

Critical value : t_c=t_{(\alpha/2,\ df)}=t_{0.005,\ 8}= 3.355

The 99% confidence interval for the population mean would be :-

\overline{x}\pm t_c\dfrac{s}{\sqrt{n}}

19.1\pm (3.355)\dfrac{1.5}{\sqrt{ 9}}\\\\=19.1\pm1.6775\\\\=(19.1-1.6775,\ 19.1+1.6775)\\\\=(17.4225,\ 20.7775)\approx(17.42,\ 20.78)

Hence, the 99% confidence interval for the population mean is (17.42, 20.78) .

7 0
3 years ago
X over 3 is less then or equal to 5
Trava [24]

Answer:

x/3 ≤ 5

I'm not sure if this is what you were looking for. If not, please be more specific in your questions!

7 0
2 years ago
Read 2 more answers
Please help me I really need help
elixir [45]

Answer:

56

Step-by-step explanation:

Lowest Common Multiple= 56

8 0
3 years ago
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Find the next number in the sequence: "-1, 1, 4, 8, 13, ..."
Afina-wow [57]

Answer:

19

Step-by-step explanation:

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