I really need help. Only do number 8. please someone.
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Answer:
<h2><em>46.4°</em></h2>Step-by-step explanation:
Find the diagrammatic representation in the attachment given.
We can see that the diagram is a right angled triangle. To get the angle of elevation, we will use one of the trigonometry identity SOH, CAH, TOA.
Given the adjacent of the triangle to be 2miles (observation spot from the point of launch)and the opposite (side facing the elevation angle) as 2.1miles (the height), we will use TOA.
tan∅ = opposite/adjacent
tan∅ = 2.1/2
tan∅ = 1.05
∅ = tan⁻¹1.05
∅ = 46.4°
<em>Hence the angle of elevation from Kim to the space shuttle, which is at a height of 2.1 miles is approximately 46.4°</em>
