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OverLord2011 [107]
4 years ago
6

Multiply each polynomial (x - 7)(x - 4)

Mathematics
1 answer:
german4 years ago
8 0

Answer:2x+28 100% right

Step-by-step explanation:

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How do you write 5 18/1000 as a decimal.
Katena32 [7]

The correct way to write 5 18/1000 as a decimal is

5.018

5 is a whole number so the decimal would go after the 5.

6 0
4 years ago
A) 18c^2 – 2(3c – 1)^2 <br>В) (2a +3)(a −3) – 2a(4 – 6a)<br>С) (2x + 3)(3 —2x) - (2x – 5)^2 –10x​
Galina-37 [17]

$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$

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Sorry,

For a), 18c^2 - 18c^2 = 0

Not = 36c^2

6 0
3 years ago
Find a formula for the nth partial sum of the series and use it to find the series' sum if the series converges.
Arisa [49]

Answer: S_n=5(1-\dfrac{1}{n+1}) ; 5

Step-by-step explanation:

Given series : [\dfrac{5}{1\cdot2}]+[\dfrac{5}{2\cdot3}]+[\dfrac{5}{3\cdot4}]+....+[\dfrac{5}{n\cdot(n+1)}]

Sum of series = S_n=\sum^{\infty}_{1}\ [\dfrac{5}{n\cdot(n+1)}]=5[\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}]

Consider \dfrac{1}{n\cdot(n+1)}=\dfrac{n+1-n}{n(n+1)}

=\dfrac{1}{n}-\dfrac{1}{n+1}

⇒ S_n=5\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}=5\sum^{\infty}_{1}[\dfrac{1}{n}-\dfrac{1}{n+1}]

Put values of n= 1,2,3,4,5,.....n

⇒ S_n=5(\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+......-\dfrac{1}{n}+\dfrac{1}{n}-\dfrac{1}{n+1})

All terms get cancel but First and last terms left behind.

⇒ S_n=5(1-\dfrac{1}{n+1})

Formula for the nth partial sum of the series :

S_n=5(1-\dfrac{1}{n+1})

Also, \lim_{n \to \infty} S_n = 5(1-\dfrac{1}{n+1})

=5(1-\dfrac{1}{\infty})\\\\=5(1-0)=5

4 0
3 years ago
jorge took a speed reading class last saturday from 9 am to 4 pm. he learned that he can speed read 330 pages of a novel in one
garri49 [273]

Answer:

1hr = 60min

225min/ 60min = 3.75 hr

330 pgs. * 3.75hr = 1237.5 pages

He read 1237.5 pages in 225 minutes.

7 0
3 years ago
Expression A: X+3 Expression B: 1 + x + 2 Which statement can be used to show that these expressions are equivalent?
mariarad [96]

Answer:

The expressions name the same number regardless of the value of x

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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