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leonid [27]
3 years ago
6

Help please! detailed would be great!

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
8 0
The goal here is to lose all those denominators so we can solve for y.  The common is found by first factoring everything that can be factored  2y-8 factors to 2(y-4) and y^2-16 factors to (y-4)(y+4).  The GCF then we will use for cancellation of the denominators is 2(y-4)(y+4).  The first term there, when multiplied by that GCF, will cancel with 2(y-4), leaving us with -8(y+4), no more denominator.  Going to the next term, when we multiply by the GCF the cancellation happens with the (y+4) term leaving us with no denominator anymore and 2*5(y-4), which simplifies to 10(y-4).  Last term.  The cancellation happens with the (y+4)(y-4), leaving us with 2(7y+8).  Putting all that together looks like this now: -8(y+4)=10(y-4)-[2(7y+8)].  Distributing gives us -8y-32=10y-40-[14y+16]  which simplifies to -8y-32=10y-40-14y-16.  We will combine like terms to get 0=4y-24.  We can factor out the 4 to get 4(y-6)=0.  Now of course 4 doesn't equal 0, but y - 6 = 0 and y = 6.  Last choice above.  There you go!
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Lana71 [14]

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Which statement compares the two numbers correctly?
Pie

Hey there! We are given two decimal numbers to compare.

52.311 and 52.31

These two numbers are similar except that 52.311 has another 1 in while 51.31 doesn't.

Keep in mind that 52.31 can also refer to 52.310

So we are comparing 52.311 and 52.310

Since 1 is greater than 0.

52.311 is greater than 52.31 (52.311 > 52.31)

Let me know if you have any questions!

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