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Crazy boy [7]
3 years ago
15

How would i solve. been getting wrong a and b

Mathematics
1 answer:
Fynjy0 [20]3 years ago
5 0

Answer:

a) 188400

b)125600

Step-by-step explanation:

Add yes and no votes together

188400 times 2/3

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In evaluating a double integral over a region D, a sum of iterated integrals was obtained as follows:
BabaBlast [244]

Answer

a=0, b=2

g_1(x)=\frac{5x}{2},  g_2(x)=7-x

Step-by-step explanation:

Given that

\int \int   Df(x,y)dA=\int_0 ^5\int _0 ^ {\frac {2y}{5}} f(x,y)dxdy+\int_5^7\int_0^{7-y} f(x,y)dxdy\; \cdots (i)

For the term  \int_0 ^5\int _0 ^ {\frac {2y}{5}} f(x,y)dxdy.

Limits for x is from x=0 to x=\frac {2y}{5} and for y is from y=0 to y=5  and the region D, for this double integration is the shaded region as shown in graph 1.

Now, reverse the order of integration, first integrate with respect to y then with respect to x . So, the limits of y become from y=\frac{5x}{2} to y=5 and limits of x become from x=0 to x=2 as shown in graph 2.

So, on reversing the order of integration, this double integration can be written as

\int_0 ^5\int _0 ^ {\frac {2y}{5}} f(x,y)dxdy=\int_0 ^2\int _ {\frac {5x}{2}}^5 f(x,y)dydx\; \cdots (ii)

Similarly, for the other term  \int_5 ^7\int _0 ^ {7-y} f(x,y)dxdy.

Limits for x is from x=0 to x=7-y and limits for y is from y=5 to y=7  and the region D, for this double integration is the shaded region as shown in graph 3.

Now, reverse the order of integration, first integrate with respect to y then with respect to x . So, the limits of y become from y=5 to y=7-x and limits of x become from x=0 to x=2 as shown in graph 4.

So, on reversing the order of integration, this double integration can be written as

\int_5 ^7\int _0 ^ {7-y} f(x,y)dxdy=\int_0 ^2\int _5 ^ {7-x} f(x,y)dydx\;\cdots (iii)

Hence, from equations (i), (ii) and (iii) , on reversing the order of integration, the required expression is

\int \int   Df(x,y)dA=\int_0 ^2\int _ {\frac {5x}{2}}^5 f(x,y)dydx+\int_0 ^2\int _5 ^ {7-x} f(x,y)dydx

\Rightarrow \int \int   Df(x,y)dA=\int_0 ^2\left(\int _ {\frac {5x}{2}}^5 f(x,y)+\int _5 ^ {7-x} f(x,y)\right)dydx

\Rightarrow \int \int   Df(x,y)dA=\int_0 ^2\int _ {\frac {5x}{2}}^{7-x} f(x,y)dydx\; \cdots (iv)

Now, compare the RHS of the equation (iv) with

\int_a^b\int_{g_1(x)}^{g_2(x)} f(x,y)dydx

We have,

a=0, b=2, g_1(x)=\frac{5x}{2} and g_2(x)=7-x.

3 0
3 years ago
7. What is the slope of the line that passes through the pair of points (3, 8) and (9, 5) ? (1 point)
agasfer [191]
7. D
8. D
9. D
10.C

for 7 & 8 you use the equation
\frac{y2 - y1}{x2 - x1}
your points are (3,8) & (9,5)

so you plug the numbers in
y2= 5
y1=8

x2=9
x1=3
you subtract them get a fraction and that is your slope


9 & 10
use the equation
y - y1 = m(x - x1)
plug you numbers in for y1 and x2 m is your slope plug it in and that is your equation


5 0
3 years ago
Read 2 more answers
Can someone help me?​
Norma-Jean [14]

Answer: 26

Step-by-step explanation:

32-6 = 26

8 0
3 years ago
Read 2 more answers
Please help and thank you
Sauron [17]

Answer: c

Step-by-step explanation:

The two points on the line are open, so they will not be included in the solution set, which means they will be greater than or less than. No number can fit both inequalities, so it must be “or”. The only one that fits this is c.

4 0
3 years ago
11. How many
Gelneren [198K]

Answer:

6 just multiply 2 times 3

8 0
2 years ago
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