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Alexeev081 [22]
3 years ago
10

Suppose you want to buy one pair of pants and several pairs of socks.

Mathematics
1 answer:
dedylja [7]3 years ago
3 0

Answer:

8

Step-by-step explanation:

50/5.95

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15=-3(2c+d) solve for c
lorasvet [3.4K]

Answer:

c = \frac{-5-d}{2}

Step-by-step explanation:

Given

15 = - 3(2c + d) ( divide both sides by - 3 )

- 5 = 2c + d ( subtract d from both sides )

- 5 - d = 2c ( isolate c by dividing both sides by 2 )

\frac{-5-d}{2} = c

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3 years ago
What information can you learn from reading a box plot graph? Be sure to explain each part of this type of graph and the informa
Minchanka [31]

Answer:

A boxplot is a standardized way of displaying the distribution of data based on a five number summary minimum, first quartile, median, third quartile , and maximum. It can tell you about your outliers and what their values are. It can also tell you if your data is symmetrical, how tightly your data is grouped, and if and how your data is skewed.

Step-by-step explanation:

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7 0
3 years ago
I need to know how to write this word problem in an algebraic expression with answer at 8 a.m. to automobile started from the sa
frutty [35]
Let time is t

since they both went in opposite directions then the distance between them is the sum of the distance between each of them and the origin point

49t + 56t =420  is the equation

to solve: 105t = 420 , t = 4 hours
8 0
3 years ago
V=4/3? r^2 Suppose that, for the sphere in the video, instead of being told how fast the radius is changing, we're told that the
grigory [225]

Answer:

\frac{dr}{dt}=0.01cm per second

\frac{dS}{dt}=320 square  centimeter per secondStep-by-step explanation:We are given that volume of sphere [tex]V=\frac{4}{3}\pi r^3

Volume of sphere is increasing at a constant rate

\frac{dV}{dt}=4 cubic centimeters per second

We have to find the rate of  radius at which increasing

when r= 10 cm

Differentiating w.r.t time

\frac{dV}{dt}=\frac{4}{3}\pi\cdot3r^2\frac{dr}{dt}

4=4 r^2\frac{dr}{dt}

\frac{dr}{dt}= \frac{1}{r^2}=\frac}{1}{(10)^2}=0.01 cm per second

Now ,we are given that surface area of sphere

S=4\pir^2

Differentiate w.r.t time then we get

\frac{dS}[dt}=8\pir\frac{dr}{dt}

\frac{dS}{dt}=8\pi\times 20\times 2

\frac{dS}{dt}=320cm per second

5 0
3 years ago
The product o 4z and 0 is
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The Government 45 is the first to graduate from school
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