Answer:
2/3,1,3/2,9/4,27/8
Step-by-step explanation:
f(1)=2/3
f(n)=f(n-1)×3/2
f(2)=f(2-1)×3/2=f(1)×3/2=2/3×3/2=1
f(3)=f(3-1)×3/2=f(2)×3/2=1×3/2=3/2
f(4)=f(4-1)×3/2=f(3)×3/2=3/2×3/2=9/4
f(5)=f(5-1)×3/2=f(4)×3/2=9/4×3/2=27/8
To calculate distance between two points we use the distance formula sqrt((x2−x1)^2+(y2−y1)^2).
To start, we find the square of the distance between x1 and x2 and y1 and y2. The distance between x1 and x2, or 1 and 3, is 2. The distance between y1 and y2, or 3 and -4, is 7.
Now we square 2 and 7 and add them together to get 4 + 49 = 53.
The last thing we do to find the distance is take the square root of 53. 53 is not a perfect square and is also a prime number so our answer in simplest form is still sqrt53.<span />
Angle C and the 112 degree angle are supplementary, so angle C measures 180-112=68 degrees.
This means that by the exterior angle theorem, 
Answer:
∠DAB = ∠DBA
Then AD=DB from above statement
the frequency of the sinusoidal graph is 2 in 2 π interval
Step-by-step explanation:
The frequency of the graphs refers to the number of the cycles, the graph completes in a given fixed interval.
We already know the formula that
P= (1/ F)
Thus, F= (1/ P)
Where F= frequency and P= Period
Period is the horizontal length (x- axis component) of one complete cycle.
Thus, Observing the above graph
We find that the graph completes 1 cycle in π interval and 2 cycles in 2π interval
Thus, the frequency of the sinusoidal graph is 2 in 2 π interval
