The answer is a hope it helps
To find the cofactor of
![A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%265%263%5C%5C-7%264%26-1%5C%5C-8%262%261%5Cend%7Barray%7D%5Cright%5D)
We cross out the Row and columns of the respective entries and find the determinant of the remaining
matrix with the alternating signs.
























Therefore in increasing order, we have;

Wooooooo hoooooooo you goooooooo
A vin diagram I'm pretty sure. or maybe drugs pflucked my brain up. js
We notice that the upper trapezoid is symmetric to the lower one & the line of symmetry should be a horizontal line (mirror line) where any point of the upper vertices should be at equal distance (perpendicular) with the related vertices of the lower one from this horizontal line:
Note that QQ" =4 units, Hence the line of symmetry is the perpendicular to QQ' at 2 units