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sveta [45]
4 years ago
15

How to find common denominators

Mathematics
1 answer:
qaws [65]4 years ago
6 0
Ok, It's hard to explain so I'll use an example. 
1/5  +   2/15
now you try to find a number that goes into both for this example it would be 3
3*5=15      and then that equals the 2/15
so you then multiply 3 by the numerator getting the fraction
3/15 + 2/15
with the answer of 
5/15 which can be reduced to
1/3

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6 0
3 years ago
Under a microscope, ms. kapinski studies a culture with bacteria. as the number of hours progresses, ms. kapinski sees that the
velikii [3]

Answer:

Study 1 Answers:

1) 0.76 represents the multiplier of the bacteria, in this case it is decreasing by 24% because the formula for exponential decay is 1 - r.

2) 1290 represents the initial value, or before the study began.

Study 2 Answers:

1) 1180 is the initial value, or before the study began.

2) Study 1 started with more bacteria

3) Study 1 is experiencing exponential decay, while study 2 is experiencing exponential growth

Step-by-step explanation:

Exponential functions are in the form y=a(b)^x, where a is the initial value, b is the multiplier, and x represents inputs, such as hours after a bacteria study.

Any multiplier above 1.00 is experiencing exponential growth, meaning it grows gradually over time, and any multiplier below 1.00 is experiencing exponential decay, meaning it decreases in population over time.

5 0
3 years ago
Complete the square to form a perfect-square trinomial.
alex41 [277]

Answer:

I think it’s a it’s tricky

Step-by-step explanation:

7 0
3 years ago
6/2-(5-4)+2(8-2/2)÷8
Firdavs [7]

Answer:

3\frac{3}{4}=\frac{15}{4} =3.75

Step-by-step explanation:

Hope this helps.

7 0
3 years ago
2x-5y=9<br> 3x+4y=2<br> solve the simultaneous equations
wariber [46]

\huge\boxed{x=2;\ y=-1}

\left\{{{2x-5y=9}\atop{3x+4y=2}}\right

First, we will solve the second equation for x. Subtract 4y from both sides of the second equation.

3x=2-4y

Divide both sides of the second equation by 3.

x=\frac{2}{3}-\frac{4}{3}y

\left\{{{2x-5y=9}\atop{x=\frac{2}{3}-\frac{4}{3}y}}\right

Substitute the value of x from the second equation into the first.

\left\{{{2(\frac{2}{3}-\frac{4}{3}y)-5y=9}\atop{x=\frac{2}{3}-\frac{4}{3}y}}\right

2(\frac{2}{3}-\frac{4}{3}y)-5y=9

We will solve the first equation for y.

Distribute the 2 to the (\frac{2}{3}-\frac{4}{3}y).

\frac{4}{3}-\frac{8}{3}y-5y=9

Combine the like terms.

\frac{4}{3}-\frac{23}{3}y=9

Add \frac{4}{3} on both sides.

-\frac{23}{3}y=9-\frac{4}{3}

-\frac{23}{3}y=\frac{23}{3}

Divide both sides by \frac{23}{3}.

-y=1

Multiply both sides by -1.

y=\boxed{-1}

Substitute the value of y into the second equation.

\left\{{{y=-1}\atop{x=\frac{2}{3}-\frac{4}{3}y}}\right

x=\frac{2}{3}-\frac{4}{3}*-1

Multiply.

x=\frac{2}{3}+\frac{4}{3}

Add.

x=\frac{6}{3}

x=\boxed{2}

5 0
3 years ago
Read 2 more answers
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