The _____ measures your level of education.

Mathematics

1 answer:

brilliants [131]3 years ago

8 0

Answer:I think it is A sorry if I am incorrect

Step-by-step explanation:

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I need to know how to simplify the sqrt or 432

Arlecino [84]

Answer:

$\sqrt{16 \times9 \times 3 \: \: equals \:4 \times 3 \times \sqrt{3that \: eauas \: 12 \sqrt{3} } }$

Step-by-step explanation:

Square root of 16 ×9×3= square root of 432

square root of 16 =4

square root of 9 =3

That will equal 4×3× square root of 3 which finally equals to 12 square root of 3.

6 0

3 years ago

Read 2 more answers

Please help I'm not sure what to do first.

nadezda [96]

Answer:

Step-by-step explanation:

it has to be under 90 degrees

7 0

3 years ago

Given that f(x) = 19x2 + 152, solve the equation f(x) = 0

telo118 [61]

Option A

The solution is:

$x = \pm 2i \sqrt{2}$

Solution:

$f(x) = 19x^2+152$

We have to solve the equation f(x) = 0

Let f(x) = 0

$0=19x^2+152$

Solve the above equation

$19x^2 + 152 = 0$

$\mathrm{Subtract\:}152\mathrm{\:from\:both\:sides}\\\\19x^2+152-152=0-152\\\\Simplify\ the\ above\ equation\\\\19x^2 = -152\\\\\mathrm{Divide\:both\:sides\:by\:}19\\\\\frac{19x^2}{19} = \frac{-152}{19}\\\\x^2 = -8$

Take square root on both sides

$x = \pm \sqrt{-8}\\\\x = \pm \sqrt{-1}\sqrt{8}\\\\\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i\\\\x = \pm i\sqrt{8}\\\\x = \pm i \sqrt{2 \times 2 \times 2}\\\\x = \pm 2i\sqrt{2}$