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Sladkaya [172]
3 years ago
13

Can someone please help me with this!! I will award brainliest and 15 points for best answer!!

Mathematics
1 answer:
vekshin13 years ago
6 0
By using Nathan's expression, Mitchel should have received 2 1/4 pounds of lemon drops. By using Darren's expression, Mitchel should have received  2 1/4 pounds of lemon drops. The difference in the amount of lemon drops Mitchel should have received using Nathan's expression instead of Darren's expression is 0 pounds.
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Create a system of linear equations that when solved algebraically, prove to have no solution.
ZanzabumX [31]

Answer: y = 3x + 4 and y = 3x + 7

Step-by-step explanation:

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3 years ago
Nom nom nom nom<br> ,<br> .<br> .<br> .<br> .
svlad2 [7]

Answer:

\fbox{\bf \red{Negative}}

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3 years ago
Ping is deciding what to choose for dinner from the menu. He can choose 1 of 3 pasta meals, 1 of 7 chicken meals, or 1 of 3 fish
lutik1710 [3]
Given:
1 of 3 pasta meals
1 of 7 chicken meals
1 of 3 fish meals

Simply multiply the total number of choices: 

3 x 7 x 3 = 63

Ping can choose a dinner meal in 63 ways.
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4 years ago
Read 2 more answers
PLS NO LINKS, rlly need help
maksim [4K]

Answer:

not sure about this one.

7 0
2 years ago
Rationalize the denominator of $\frac{5}{2+\sqrt{6}}$. The answer can be written as $\frac{A\sqrt{B}+C}{D}$, where $A$, $B$, $C$
horrorfan [7]

Answer:

A +B+C+D  = 3 is the correct answer.

Step-by-step explanation:

Given:

$\frac{5}{2+\sqrt{6}}$

To find:

A+B+C+D = ? if given term is written as following:

$\frac{A\sqrt{B}+C}{D}$

<u>Solution:</u>

We can see that the resulting expression does not contain anything under \sqrt (square root) so we need to rationalize the denominator to remove the square root from denominator.

The rule to rationalize is:

Any term having square root term in the denominator, multiply and divide with the expression by changing the sign of square root term of the denominator.

Applying this rule to rationalize the given expression:

\dfrac{5}{2+\sqrt{6}} \times \dfrac{2-\sqrt6}{2-\sqrt6}\\\Rightarrow \dfrac{5 \times (2-\sqrt6)}{(2+\sqrt{6}) \times (2-\sqrt6)} \\\Rightarrow \dfrac{10-5\sqrt6}{2^2-(\sqrt6)^2}\ \ \ \ \   (\because \bold{(a+b)(a-b)=a^2-b^2})\\\Rightarrow \dfrac{10-5\sqrt6}{4-6}\\\Rightarrow \dfrac{10-5\sqrt6}{-2}\\\Rightarrow \dfrac{-5\sqrt6+10}{-2}\\\Rightarrow \dfrac{5\sqrt6-10}{2}

Comparing the above expression with:

$\frac{A\sqrt{B}+C}{D}$

A = 5, B = 6 (Not divisible by square of any prime)

C = -10

D = 2 (positive)

GCD of A, C and D is 1.

So, A +B+C+D = 5+6-10+2 = \bold3

5 0
3 years ago
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