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mariarad [96]
3 years ago
12

Last​ year, my parents had a combined income of

Mathematics
1 answer:
marin [14]3 years ago
3 0
13,000 / 50,000 = 13/50
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Find all values of x for which the series converges. (enter your answer using interval notation. ) [infinity] (4x)n n = 1
andreyandreev [35.5K]

The series converges to  1/(1-9x) for -1/9<x<1/9                  

Given the series is  ∑ 9x^{n} x^{n}

We have to find the values of x for which the series converges.

We know,                

∑ ar^{n-1}    converges to  (a) / (1-r) if r < 1

Otherwise the series will diverge.

Here, ∑ (9x)^{n} is a geometric series with |r| = | 9x |

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Here, a = 1 and r = 9x

Therefore, a/(1-r) = 1/(1-9x)

Hence, the given series converges to   1/1-9x  for  -1/9<x<1/9

For more information about convergence of series, visit

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1 year ago
Can someone help last one :((
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Answer:

40.49cm²

Step-by-step explanation:

I hope it helps

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A spinner with 9 equal sections is numbered 1 through 9. The probability of spinning a 1 or a 9 is 2/9 . What is the probability
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8/10+9/10=17/10=1 7/10=2
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