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3 years ago

9

The formula to find the surface area of a cube is 6s to the power of 2, where s stands for the side length of the cube. What is

the surface area of the cube if it’s side length is 10cm?

1 answer:

gladu [14]3 years ago

3 0

The surface area of the cube is 600cm^2.

6(10^2)
6(100)
600

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V=(4/3) (3.14) (3^3)

marysya [2.9K]

Answer:

Step-by-step explanation:

V = (4/3)(3.14)(3^3)

V = 4/3 * 27 * 3.14

V = 36 * 3.14

V = 113.04

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3 years ago

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2 years ago

Explain why a triangle can't have two right angles

Sedbober [7]

Answer: They would be a rectangle.

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3 years ago

Evaluate using <br> Definite integrals

swat32

Since $[0,4]=[0,1]\cup(1,4]$ , we can rewrite the integral as

$\displaystyle \int_0^1f(t)\;dt + \int_1^4 f(t)\; dt$

Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:

$\displaystyle \int_0^1f(t)\;dt = \int_0^11-3t^2\;dt,\quad \int_1^4 f(t)\; dt = \int_1^4 2t\; dt$

Both integrals are quite immediate: you only need to use the power rule

$\displaystyle \int x^n\;dx=\dfrac{x^{n+1}}{n+1}$

to get

$\displaystyle \int_0^11-3t^2\;dt = \left[t-t^3\right]_0^1,\quad \int_1^4 2t\; dt = \left[t^2\right]_1^4$

Now we only need to evaluate the antiderivatives:

$\left[t-t^3\right]_0^1 = 1-1^3=0,\quad \left[t^2\right]_1^4 = 4^2-1^2=15$

So, the final answer is 15.

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3 years ago