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a_sh-v [17]
3 years ago
7

-2x + 3 > 3(2x - 1) How do i solve this inequality? PLEASE HELP

Mathematics
2 answers:
Len [333]3 years ago
5 0
First, you need to distribute on the right side, then it would be -2x + 3 > 6x -3 then you would add 2x to both sides to get 3 > 8x -3 then you add 3 to each side to get 6 > 8x. Now you divide by 8 to get 6/8 that simplified is 3/4. X=3/4
Nataly_w [17]3 years ago
3 0
X=3/4 hope this helped
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M is the midpoint of LN. What is the measure of LM= 3x and LN= 2x + 2, find LM.
raketka [301]

Answer:

LM = 1.5

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Step-by-step explanation:

From the question given:

M is the midpoint of LN

LM = 3x

LN= 2x + 2

LM =.?

Next, we shall determine the value of x. This is illustrated below:

Since M is the midpoint of LN, it means that when we divide LN by 2 the result will be LM i.e

LN /2 = LM

With the above formula, we can obtain the value of x as follow:

LN= 2x + 2

LM = 3x

x =..?

LN /2 = LM

2x + 2/ 2 = 3x

Cross multiply

2 × 3x = 2x + 2

6x = 2x + 2

Collect like terms

6x - 2x = 2

4x = 2

Divide both side by 4

x = 2/4

x = 0.5

Finally, we can obtain LM and LN as follow:

LM = 3x

x = 0.5

LM = 3 × 0.5

LM = 1.5

LN= 2x + 2

x = 0.5

LN = 2(0.5) + 2

LN = 1 + 2

LN = 3

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3 years ago
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6x+7=

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Step-by-step explanation:

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Find the point (x,y)<br>on the line y = x that is equidistant from the points (-6,2) and (10,-9)​
Nezavi [6.7K]

Answer:

(14.1, 14.1)

Step-by-step explanation:

If the point (x,y) is on the line y=x, then it has coordinates (x,x).

Find the distances from this point to points (-6,2) and (10,-9):

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Equate these distances:

\sqrt{(x+6)^2+(x-2)^2}=\sqrt{(x-10)^2+(x+9)^2}

Square this equation:

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So, the coordinates are (14.1, 14.1)

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