Answer:
In picture...
Step-by-step explanation:
I solved it step by step in picture. U can have a look
✌️
Answer:
x=32, x=0
Step-by-step explanation:
![(x-16)^2=256](https://tex.z-dn.net/?f=%28x-16%29%5E2%3D256)
Take the square root of both sides
![\sqrt{ (x-16)^2}=\±\sqrt{256}\\x-16=\±16](https://tex.z-dn.net/?f=%5Csqrt%7B%20%28x-16%29%5E2%7D%3D%5C%C2%B1%5Csqrt%7B256%7D%5C%5Cx-16%3D%5C%C2%B116)
x=16+16 or x=16-16
Therefore, x=32 or x=0
I hope this helps!
Answer:
y=1/2x-3
Step-by-step explanation:
Hope this helps :) Have a great day!!!
10
using the second equation you can get s=-2. then plugging that into the first you get
-9(-2)-8 = 18-8 = 10
1) let's convert the maximum altitude of the black kite from feet to meters. We can do it by using the following proportion:
![1 ft : 0.3048 m = 362.26 ft : x](https://tex.z-dn.net/?f=1%20ft%20%3A%200.3048%20m%20%3D%20362.26%20ft%20%3A%20x)
From which we find
![x=110.42 m](https://tex.z-dn.net/?f=x%3D110.42%20m)
This is the maximum altitude (in meters) of the black kite. The problem says that the maximum altitude of the red kite is 117.46 m, therefore the red kite is the one with higher maximum altitude.
2) Let's convert the maximum altitude of the red kite from meters to feet, again by using the proportion:
![1 ft : 0.3048 m = x : 117.46 m](https://tex.z-dn.net/?f=1%20ft%20%3A%200.3048%20m%20%3D%20x%20%3A%20117.46%20m)
From which we find
![x=385.37 ft](https://tex.z-dn.net/?f=x%3D385.37%20ft)
Therefore, the maximum altitude of the red kite in feet is 385.37 ft.