Answer:
See step by step explanations fir answers.
Step-by-step explanation:
Given that;
n=6 , m=2 , z1 is the average of the elements of x , and z2 is the average of the first three elements of x minus the average of fourth through sixth elements of x
So, Let d=n∧28, d′=n∧22.
We have nd=10, nd′=20n
so
n=10d=20d′nwhenced=2d′.
On the other hand, d is a divisor of 28, and above shows d′ is, too. As it is also a divisor of 22, the only possibilities are d′=1, d′=2, corresponding to d=2, d=4.
However, if d=2, n=20, and 20∧28=4, not 2. So the only solution is d=4, and n=40.
Answer:
Step-by-step explanation:
t1 means a1 and t7 means a7
a+(n-1)d=an
a+(1-1)d=4
so we get a as 4
<u><em>a=4</em></u>
a+(n-1)d=an
4+(7-1)d=22
4+6d=22
6d=22-4
d=18/6
<u><em>d=3</em></u>
Answer:
A!
Step-by-step explanation:
Answer:
347 + 645 = 992
Step-by-step explanation:
347
<u>+645</u>
922
(2j+7)(2j−7)
=(2j+7)(2j+−7)
=(2j)(2j)+(2j)(−7)+(7)(2j)+(7)(−7)
=4j2−14j+14j−49
=4j2−49