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3 years ago

What is the value of –2|6x – y| when x = –3 and y = 4?

Mathematics

2 answers:

irakobra [83]3 years ago

8 0

Answer:

The correct answer is -44

Step-by-step explanation:

Points to remember

|x| = x

|-x| = x

To find the value of –2|6x – y| 

We have –2|6x – y| When x = -3 and y = 4

Substitute the value of x and y

–2|6x – y| = –2|(6 * -3) – 4|

= -2|-18 - 4|

= -2|-22|

= -2 * 22

= -44

Therefore the value of –2|6x – y| when x = -3 and y = 4

–2|6x – y|

kenny6666 [7]3 years ago

5 0

Answer:

-44

Step-by-step explanation:

We have the expression

$-2|6x - y|$

We need to find the value of the expression when x = -3 and y = 4

Then we must replace the variable with the number -3 and the variable y with the number 4

This is:

$-2|6(-3) - (4)|$

$-2|-18 - 4|$

$-2|-22|$

Remember that the absolute value always results in a positive number.

$-2|-22| = -2(22)=-44$

the answer is -44

You might be interested in

Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.

melamori03 [73]

Answer:

$6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}$

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs $AB=3$ , $BC=4$ , and $AC=5$ . The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base $b$ and height $h$ is given by $A=\frac{1}{2}bh$ . Therefore, the area of this right triangle is:

$A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}$

The other triangle is a bit trickier. Triangle $\triangle ADC$ is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by: