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Hitman42 [59]
3 years ago
10

3x+12-6x<-9

3x + 12 - 6x \leqslant - 9" alt="3x + 12 - 6x \leqslant - 9" align="absmiddle" class="latex-formula">
how do I do this?
Mathematics
1 answer:
saveliy_v [14]3 years ago
8 0
First simplify 3x + 12 - 6x to -3x - 12
Next subtract 12 from both sides
Next subtract -9 - 12 and that would be -21
Next divide both sides by -3
Next lets simplify the fraction -21/-3 into 21/3 since those two negatives make a positive.
Lastly simplify the fraction 21/3 to get the answer.


Answer: x ≥ 7

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Given that average mass of an ant = 3 \times 10^{-3}grams.

Given that average mass of a giraffe = 2 \times 10^{3} Kilograms.

Now we have to find about how many times more mass does a giraffe have than an ant. Before carring out any comparision, we must make both units equal.

Like convert kilogram into gram or gram into kilogram.

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Now we just need to divide mass of giraffe by mass of ant to find the answer.

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