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2 years ago

What is the length of the hypotenuse of the triangle?

Mathematics

2 answers:

saw5 [17]2 years ago

8 0

Answer:

37.7

Step-by-step explanation:

Hypotenuse is the longest side

Eduardwww [97]2 years ago

3 0

Answer:

answer is b

Step-by-step explanation:

we need a picture of the triangle

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The bases of a circular cylinder are two ___ circles.

Blababa [14]

Well,

A cylinder is actually a special type of prism. A prism is a 3-D figure made by taking a simple closed plane curve and translating it across space in a certain direction and for a given distance and then connecting the preimage and the image. A cylinder is just a prism made with a circle.

We know from translations that the image is congruent to the preimage. Thus, the bases of a (circular) cylinder are two congruent circles.

6 0

3 years ago

Read 2 more answers

The center on a target has a diameter of 5 inches. The whole target has a diameter of 25 inches. The center of the target takes

Komok [63]

4%

To find the percentage, first find the area of both circles. The area formula is $\pi r^{2}$ . After finding the area of the center of the target (19.625) and the area of the large target (490.625), set up a percent proportion to determine the percentage that the center takes up:

$\frac{is}{of} = \frac{percent}{100}$

$\frac{19.625}{490.625} = \frac{percent}{100}$

Cross multiplying and dividing by 490.625 will give a total of 4%.

4 0

2 years ago

A regular hexagon is shown.

zhuklara [117]

The central angle of the hexagon is equal to 60º.

Therefore, the trigonometric relationship for the radius is given by:

$cos (30) = \frac{a}{c}$

Where,

a: apothema of the hexagon

c: Hexagon radius.

Clearing the radio we have:

$c = \frac{a}{cos (30)}$

Substituting values:

$c = \frac{12}{cos (30)} c = 13.85$

Rounding to the nearest whole number we have:

$c = 14 in$

Answer:

The measure of the radius, c, rounded to the nearest inch is:

C. 14 in.

7 0

2 years ago

Read 2 more answers

5tanx-2cotx+1=0...... .

Verdich [7]

Step-by-step explanation:

5(tanx)^2 -2 +tanx=0

let tanx=y

5y^2 + y-2=0

y=0.5403 or y= -0.7403

tanx=0.5403

x=arctan(0.5403)

x=28.38°

tanx=-0.7403

x=arctan(-0.7403)

x=143.49°

7 0

2 years ago

Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1

defon

I'm guessing the series is supposed to be

$\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}$

By the ratio test, the series converges if the following limit is less than 1.

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|$

The first $n$ terms in the numerator's denominator cancel with the denominator's denominator:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|$

$|x^n|$ also cancels out and the remaining factor of $|x|$ can be pulled out of the limit (as it doesn't depend on $n$ ).

$\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0$

which means the series converges everywhere (independently of $x$ ), and so the radius of convergence is infinite.

3 0

3 years ago