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Ivan
4 years ago
14

Wame a pair of lines that appear to be parallel.

Mathematics
2 answers:
Ket [755]4 years ago
7 0

line AB and CD

they appear as though they are parallel

hope i helped!!!

KatRina [158]4 years ago
6 0

Answer:

AB and CD are parallel

Step-by-step explanation:

because they will never intersect

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It was 6 feet long! When the sandwich arrived, Zachary cut it into 16 equal pieces.
Gekata [30.6K]

Answer:

2.66667

Step-by-step explanation:

divide 16 by 6

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4 years ago
NP is an angle bisector of <MNO. If <MNP = x + 23, and m<PNO = 3x - 1, find the value of x.
Neko [114]

The answer is: " 12 " .

_____________________________________________

→ " x = 12 " .

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To solve:

________________________________________________________

3x - 1 = x + 23 ; Solve for "x" ;

Subtract "x" from each side of the equation; & add "1" to each side of the equation;

3x - 1 - x + 1 = x + 23 - x + 1 ;

to get:

2x = 24 ;

Divide each side of the equation by "2" ;

to isolate "x" on one side of the equation; & to solve for "x" ;

2x/2 = 24/2 ;

to get:

x = 12 .

_____________________________________________

Let us check our answer, by plugging in "12" for "x" ; on EACH side of the original equation; to see if the equation holds true; {that is, to see if each side of the original equation is equal, when "x = 12" } ; as follows:

______________________________________________

3x - 1 = x + 23 ;

Substitute "12" for "x" on each side ;

3(12) - 1 =? (12) + 23 ??

36 - 1 =? 35 ??

35 =? 35?? Yes!

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5 0
4 years ago
I need the answer for this: 7y+4/y+2=4/3
m_a_m_a [10]

Answer:

Juanita dissolves 46 g of MgBr2 (molar mass: 184.11 g/mol) in 0.5 kg of distilled water. What is the molality of the solution?

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3 years ago
Any recurring sequence of points above and below the trend line lasting less than one year can be attributed to the cyclical com
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3 years ago
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Len [333]
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Step-by-step explanation:

So we first need to assign letters to represent the numbers.

Let 'a' be the larger number and 'b' the smaller.

Now we can use this to write equations that we can solve simultaneously to find both 'a' and 'b'.

according to the question:

a + 4b  = 156  [1]

a - b = 1  [2]   (this is because the integers are consecutive

We can rearrange [2] to make 'a' the subject:     a = b + 1 [3]

We can then substitute [3]  into [1] and solve for b

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Now we can find 'a' using [3]

a = 31 + 1

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4 0
3 years ago
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