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Mandarinka [93]
3 years ago
12

865.3 divided by 5 ...?

Mathematics
1 answer:
kolbaska11 [484]3 years ago
5 0
173.06 is your answer
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Sam ran 3/5 of a mile in 1/6 of an hour. How far could he run in an entire hour?
Leno4ka [110]

Answer:

3

Step-by-step explanation:

3/5 x 6 = 3 3/5

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3 years ago
6n+3=2 use a table ....
kvasek [131]
You - 3 from 2 then do 6n=-1
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If the sum of the measures of the interior angles of a polygon is twice the sum of its exterior angles, how many sides does it h
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3 years ago
The top of the cylindrical can shown below has a diameter of 7 centimeters (cm).
Sidana [21]

Answer:

Circumference of the can is 21.98 cm.

Step-by-step explanation:

Since, top of the cylinder can shown in the figure is in the shape of a circle

Circumference of a circle is given by the formula,

Circumference 'C' = π × Diameter

Where r = radius of the circle

Therefore, circumference of a circle with diameter 7 centimeters will be,

C = 7π

   = 7 × 3.14

   = 21.98 cm

Therefore, circumference of the can is 21.98 cm.

5 0
3 years ago
Sample spaces For each of the following, list the sample space and tell whether you think the events are equally likely:
Schach [20]

Answer and explanation:

To find : List the sample space and tell whether you think the events are equally likely ?

Solution :

a) Toss 2 coins; record the order of heads and tails.

Let H is getting head and t is getting tail.

When two coins are tossed the sample space is {HH,HT,TH,TT}.

Total number of outcome = 4

As the outcome HT is different from TH. Each outcome is unique.

Events are equally likely since their probabilities \frac{1}{4} are same.

b) A family has 3 children; record the number of boys.

Let B denote boy and G denote girl.

If there are 3 children then the sample space is

{GGG,GGB,GBG,BGG,BBG,GBB,BGB,BBB}

The possible number of boys are 0,1,2 and 3.

Number of boys      Favorable outcome    Probability

           0                      GGG                        \frac{1}{8}

           1                    GGB,GBG,BGG          \frac{3}{8}

           2                   GBB,BGB,BBG           \frac{3}{8}

           3                       BBB                         \frac{1}{8}

Since the probabilities are not equal the events are not equally likely.

c)  Flip a coin until you get a head or 3 consecutive tails; record each flip.

Getting a head in a trial is dependent on the previous toss.

Similarly getting 3 consecutive tails also dependent on previous toss.

Hence, the probabilities cannot be equal and events cannot be equally likely.

d) Roll two dice; record the larger number

The sample space of rolling two dice is

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now we form a table that the number of time each number occurs as maximum number then we find probability,

Highest number        Number of times         Probability

           1                                   1                     \frac{1}{36}

           2                                  3                    \frac{3}{36}

           3                                  5                    \frac{5}{36}

           4                                  7                    \frac{7}{36}

           5                                  9                    \frac{9}{36}

           6                                  11                    \frac{11}{36}

Since the probabilities are not the same the events are not equally likely.

4 0
3 years ago
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